Y=1/2(x+8)+3 please show work also write in y=mx+b
1 answer:
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Answer:
314 ft²
Step-by-step explanation:
Data provided in the question:
Depth (height) of the pool = of its radius
let the radius be 'r' ft
thus,
Depth (height) of the pool, h = ft
Volume of the pool = 1570 ft³
also,
Volume of cylinder = πr²h
thus,
1570 ft³ = πr²h
or
1570 ft³ =
or
3140 = 3.14 × r³ [ π = 3.14 ]
or
r³ = 1000 ft³
or
r = 10 ft
Thus,
Area of the bottom surface = πr²
= 3.14 × 10²
= 314 ft²
Given :
A water well rig has dug to a height , H = 60 feet after one full day of continuous use .
To Find :
If the height is currently 143.6 feet how time it been running .
Solution :
It is given that height after 24 hours of use is 60 feet .
So , height loose in 1 hours is :
Now , time taken to cover a height of 143.6 feet is :
Therefore , time taken is 57.44 hours .
Hence , this is the required solution .