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prohojiy [21]
2 years ago
5

The figure is a parallelogram. Find the missing measures.

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
8 0

G is the center of the parallelogram, and the midpoint of both diagonals.

If CG = 7, then GE must also be 7.

CE = CG + GE = 7 + 7 = 14

CE = 14

If FD = 22, then FG must be half of 22, which is 11.

Hope this helps!

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AB←→||CD←→. Find the measure of ∠BFG.
Colt1911 [192]

Answer:

Value of ∠ BFG = 135°

Step-by-step explanation:

Given:

AB || CD

∠ AFG = (3x + 15)°

∠ FGD = (5x - 5)°

Find:

∠ BFG

Computation:

We know that;

∠ AFG = ∠ FGD

3x + 15 = 5x - 5

3x - 5x = - 5 - 15

- 2x = - 20

2x = 20

x = 10

Value of ∠ AFG = 3x + 15

Value of ∠ AFG = 3(10) + 15

Value of ∠ AFG = 45°

∠ BFG = 180° - Value of ∠ AFG

∠ BFG = 180° - 45°

∠ BFG = 135°

Value of ∠ BFG = 135°

8 0
2 years ago
Simplify this expression.<br> 3^-3
Sphinxa [80]

Answer:

1/27 is the answer

Step-by-step explanation:

It is 1/(3^3) which is 1/27

4 0
2 years ago
4 2/3 divided by 4 1/5
Galina-37 [17]
(4 2/3) / (4 1/5) = 1.111
8 0
3 years ago
Read 2 more answers
Here are descriptions for how two dot patterns are growing,
Arisa [49]

The steps in the patterns A and B form a sequence

The attached diagram represents dots in patterns A and B

<h3>How to draw the diagrams</h3>

For pattern A, we have:

Step 2 = 10 dots

Increment of 3 dots in each step

This means that:

Step 0 = 4 dots

Step 1 = 7 dots

Step 2 = 10 dots

Step 3 = 13 dots

For pattern A, we have the following rule

T_n =2n^2 + 1

When n = 0 to 3, we have:

T_0 =2(0)^2 + 1 =1

Step 0 = 1 dot

T_1 =2(1)^2 + 1 =3

Step 1 = 3 dots

T_2 =2(2)^2 + 1 =9

Step 2 =  9 dots

T_3 =2(3)^2 + 1 =19

Step 3 =  19 dots

Next, we draw the diagrams of both patterns (see attachment)

Read more about patterns at:

brainly.com/question/15590116

6 0
2 years ago
grades are due tomorrow morning and ive been struggling really bad. this is the app that has been helping me pass. i’ll give bra
ankoles [38]

Answer:

answer is a

Step-by-step explanation:

8 0
3 years ago
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