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Bezzdna [24]
3 years ago
6

Help Me! ASAP! Which of the follow statements is NOT true?​

Mathematics
2 answers:
Kobotan [32]3 years ago
7 0

Answer:

The first one is incorrect

Step-by-step explanation:

I'm sorry if this is wrong...

Amiraneli [1.4K]3 years ago
6 0

Answer:

I believe the answer is C.

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The values (9.4,11) and (11,y) are from an inverse variation. Find the missing value and round to the nearest hundredth.
marusya05 [52]

Answer: 9.4

Step-by-step explanation:

Here the x-coordinates and y-coordinates have the inverse relation.

⇒ x\propto\frac{1}{y}

⇒ x=\frac{k}{y}

Where k is variation constant.

Since, point (9.4, 11) is from the inverse variation,

Therefore, this point must be satisfy the above condition,

That is,    9.4=\frac{k}{11}

k=103.4

Thus, the relation between the coordinates is,

x=\frac{103.4}{y}

Put x = 11, in the above function,

11=\frac{103.4}{y}

y=\frac{103.4}{11}=9.4

3 0
3 years ago
Read 2 more answers
#23-6: The pool concession stand made $5,800 in June and $6,300 in July. What is the percent of increase in sales? Round the ans
katrin [286]

Answer:

8.6%

Step-by-step explanation:

To find the percent change, you will need to compute the positive difference and then divide the difference by the original (the older amount).

So the positive difference will be obtain by doing larger minus smaller:

 6300

- 5800

-----------

   500

The older amount was 5800.

So 500/5800 is the answer as a un-reduced fraction.

I'm going to reduce it by dividing top and bottom by 100:

500/5800  = 5/58

5/58 is the answer as a reduced fraction.

5 divided by 58 gives=0.086206897  in the calculator .

Approximately 0.0862 is the answer as a decimal.

To convert this to a percentage, multiply it by a 100:

8.62%

Rounded to the nearest tenths is 8.6%

-------------

So 5800+5800(.0862) should be pretty close to 6300 (not exactly though since we rounded).

5800+5800(.0862)=6299.96 using the calculator.

8 0
3 years ago
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g
givi [52]

Given :

An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.

To Find :

How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.

Solution :

Mass of copper in 50 gm alloy = 50\times 0.12 = 6\ gram.

Mass of copper in 78 gm alloy = 78\times 0.98 = 76.44\ gram.

Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.

Percentage of copper in resulting mixture :

\%=\dfrac{82.44}{50+78}\\\\\%=64.4\ \%

Hence, this is the required solution.

8 0
4 years ago
I’m confused can someone help me please
Andrej [43]
It’s 6 with a remainder of 4. So what we’re doing here is dividing 32 by 5. It’s pretty simple. Hope this helps!
6 0
3 years ago
HELP ASAP PLSSSSSSSSSSSSSSSSSS
Karo-lina-s [1.5K]

Answer:

h2= p2+b2

=15*15+8*8

=✓225+64

=✓289

=17cn

5 0
3 years ago
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