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Viefleur [7K]
2 years ago
8

-5x-y= 8 -4x+y=2 solve the system

Mathematics
1 answer:
yan [13]2 years ago
7 0

\huge\fcolorbox{blue}{aqua}{Answer:}

═════════════════════

1.- 5x - y = 8

<h3>Solve for x</h3>

-5x-y=8

-5x=8+y

-5x=y+8

\frac{-5x}{-5}=\frac{y+8}{-5}

x=\frac{y+8}{-5}

x=\frac{-y-8}{5}

<h3>Solve for y</h3>

-5x-y=8

-y=8+5x

-y=5x+8

\frac{-y}{-1}=\frac{5x+8}{-1}

y=\frac{5x+8}{-1}

y=-5x-8

────────────────────

2.-4x-y=2

<h3>Solve for x</h3>

-4x-y=2

-4x=2+y

-4x=y+2

\frac{-4x}{-4}=\frac{y+2}{-4}

x=\frac{y+2}{-4}

x=-\frac{y}{4}-\frac{1}{2}

<h3>Solve for y</h3>

-4x-y=2

-y=2+4x

-y=4x+2

\frac{-y}{-1}=\frac{4x+2}{-1}

y=\frac{4x+2}{-1}

y=-4x-2

════════════════════

Explanation:

#Carry on learning

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Answer:

a = \frac{r-q}{g}

Step-by-step explanation:

Given

ga + q = r ( subtract q from both sides )

ga = r - q ( isolate a by dividing both sides by g )

a = \frac{r-q}{g}

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Amanda went to the store to purchase ink pens. She found three kinds of pens. The first cost $4 each; the price of the second ki
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Answer:

Amanda buy first kind of pen = 3

Amanda buy second kind of pen = 2

Amanda buy third kind of pen = 15

Step-by-step explanation:

Given - Amanda went to the store to purchase ink pens. She found three    

            kinds of pens. The first cost $4 each; the price of the second kind

            was 4 for $1; and the cost for the third kind was 2 for $1. She bought

            20 pens and she bought at least one of each kind. (It is possible to

            buy only 1 of the pens that are "4 for $1" or "2 for $1".) The cost was

            $20.

To find - When she got back to her office, Amanda decided to turn this into

              a math problem for me. She asked: how many of each kind did I

              buy?

Proof -

Let Amanda buy first kind of pen = x

                      second kind of pen = y

                           third kind of pen = z

As given,

She bought total pen = 20

⇒x + y + z = 20          ...............(1)

Now,

As given,

cost for first kind pen = $4 for 1 pen

As she bought x pens of first kind , so

Cost of x pens of first kind = $4x

Now,

The price of the second kind was 4 for $1

⇒Cost of second kind = $\frac{1}{4} for 1 pen

As she bought y pens of send kind , so

Cost of y pens of second kind = $\frac{1}{4}y

Now,

The price of the third kind was 2 for $1

⇒Cost of third kind = $\frac{1}{2} for 1 pen

As she bought z pens of send kind , so

Cost of z pens of third kind = $\frac{1}{2}z

Now,

As given, The cost was $20

⇒4x + \frac{1}{4}y + \frac{1}{2}z = 20

⇒16x + y + 2z = 80             .....................(2)

∴ we get 2 equations

x + y + z = 20                   .....................(1)

16x + y + 2z = 80             .....................(2)

Now,

Subtract equation (1) from equation (2) , we get

16x + y + 2z  - ( x+ y + z )= 80 - 20

⇒16x + y + 2z - x - y - z = 60

⇒15x + z = 60

⇒z = 60 - 15x

Now,

Put the value of z in equation (1) , we get

x + y + 60 - 15 x = 20

⇒ y - 14x = 20 - 60

⇒y - 14x = -40

⇒14x - y = 40

⇒y = 14x - 40

Now,

we get

z = 60 - 15x

y = 14x - 40

As given

she bought at least one of each kind

it means x > 1, y > 1, z > 1

Now,

If x = 1, then y = 14 - 40 = -26

Not possible

If x = 2 , then y = 14(2) - 40 = -12

Not possible

If x = 3, then y = 14(3) - 40 = 2 and z = 60 - 15(3) = 15

Possible.

If x = 4,  then y = 14(4) - 40 = 16 and z = 60 - 15(4) = 0

Not Possible.

If x = 5, then y = 14(5) - 40 = 30 and z = 60 - 15(5) = -15

Not Possible.

∴ we get

x = 3, y = 2, z = 15

Amanda buy first kind of pen = x = 3

Amanda buy second kind of pen = y = 2

Amanda buy third kind of pen = z = 15

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This isn't guaranteed to happen though, that's where experimental probability comes form.

Experimental probability is the number of desired outcomes achieved, divided by the total number of outcomes.  This is based on what actually happened.  Say you selected a marble, and put it back 10 times, recording the color each time and you got 2 blue marbles.  Your experimental probability is

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