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valentinak56 [21]
3 years ago
9

Write the equation in standard form. x = -4y + 8

Mathematics
1 answer:
guapka [62]3 years ago
7 0

Answer:

x+4y=8 is the correct answer

Step-by-step explanation:

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PLEASE HELP Solve each of the proportion below using the cross‐product property.
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Answer:

D) 5/8 = a/16

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Please help !<br> I need the answers for #43 and #44
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43. 9 + 10 + 13 + 13 = $45

45 - 1 = 44

44 x 4 = 176

176 + 8 = 184

184/4 = 46

46 tokens per person

44. a. 22 x 5 = 110

943/110 = 8.7

you will need 9 bookcases

b. 110 x 9 = 990

990 - 943 = 47

47 - 44 = 3

There will be 3 books on the third shelf.

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3 years ago
My dad uses a reusable cup every time every time he goes to the coffee shop the coffee shop takes $0.10 off each coffee every ti
rosijanka [135]

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there are 7 days in a week x 0.10 cents saved each day on the week = 0.70 cents every week

Step-by-step explanation:

8 0
3 years ago
Look at the picture
ValentinkaMS [17]

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3 times the square of -3 plus -5 times -3 plus 12

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7 0
3 years ago
The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
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