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2 years ago

Write the equation in standard form. x = -4y + 8

Mathematics

1 answer:

guapka [62]2 years ago

7 0

Answer:

x+4y=8 is the correct answer

Step-by-step explanation:

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The width of the rectangle is 1/3 of the length. Find the length and width of the rectangle.

adell [148]

Answer:

1.333333333

Step-by-step explanation:

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2 years ago

Zack bought a coat for $69.78. He paid with $100 bill and received $26.73 in change. How much was the sales tax?

Klio2033 [76]

$3.49

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2 years ago

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Write a real word problem that compares <br> 0.4 and 0.29. Then solve the problem.

sesenic [268]

If a piece of candy costs .29$ and I have .40$ I will have .11$. Hope it helped

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2 years ago

Match each exponential function to the description of its percent rate of change. 22% growth 12% decay 2% decay 20% growth 20% d

makvit [3.9K]

The exponential function is defined as y = a(1+r)^x, where "a" represents the original account and "r" the rate of growth or decay.

Then we have the following:

1) 22% grow

y = a( 1 + 22%/100 )^x = a(1.22)^x

So the solution is: 124(1.22)^x

2) 12% decay

y = a( 1 - 12%/100 )^x = a(0.88)^x

So the solution is: y = f(x) = 44(0.88)^x

3) 20% decay

y = a( 1 - 20%/100 )^x = a(0.8)^x

So the solution is: f(x) = 22(0.8)

4) 12% Groth

y = a( 1 + 12%/100 )^x = a(1.12)^x

So the solution is: f(x) = 42(1.12)^x

4 0

2 years ago

Suppose an automotive repair company wants to determine the current percentage of customers who keep up with regular vehicle mai

Nina [5.8K]

Answer: 1692

Step-by-step explanation:

Formula to find the sample size :

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

Given : Confidence level : $(1-\alpha)=0.90$

⇒ significance level = $\alpha= 0.10$

z-value for 90% confidence interval (using z-table)= $z_{\alpha/2}=1.645$

Prior estimate of the population proportion (p) of customers who keep up with regular vehicle maintenance is unknown.

Let we take p= 0.5

Margin of error : E= 2%=0.02

Now, the required sample size will be :

$n=0.5(1-0.5)(\dfrac{1.645}{0.02})^2$

Simplify , we get

$n=(0.25)(6765.0625)=1691.265625\approx1692$

Hence, the required sample size = 1692

8 0

2 years ago

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