Answer:
Height = 28 inches, Base = 36 inches
Step-by-step explanation:
Height of a triangle is 4x inches and the base is (5x+1) inches.
Area of the triangle is given as 500 square inches.
We have to calculate the dimensions of the triangle.
Since area of a triangle = (1/2)×Base×height = 500
(1/2)×(4x)×(5x+1) = 500
2x(5x+1) = 500
x(5x+1) = 250
5x² + x - 250 = 0
x = 7
Therefore height = 4x = 28 inches
Base = (5x + 1) = 35+1 = 36 inches.
Answer:
x = -8
Step-by-step explanation:
Given the equation:
Note that
then
Rewrite the equation as
then
<h3><u>Given </u><u>:</u><u>-</u></h3>
- A marker in the center of the fairway is 150 yards away from the centre of the green
- While standing on the marker and facing the green, the golfer turns 100° towards his ball
- Then he peces off 30 yards to his ball
<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>
<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>
Let assume that the distance between the golf ball and central of green is x
<u>Here</u><u>, </u>
- Distance between marker and centre of green is 150 yards
- <u>That </u><u>is</u><u>, </u>Height = 150 yards
- For facing the green , The golfer turns 100° towards his ball
- <u>That </u><u>is</u><u>, </u>Angle = 100°
- The golfer peces off 30 yards to his ball
- <u>That </u><u>is</u><u>, </u>Base = 30 yards
<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>
- Here, a = perpendicular height
- b = base
- c = hypotenuse
- cos theta = Angle of cosine
<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards
Answer:
15in
Step-by-step explanation:
Answer:
90°
Step-by-step explanation:
Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.
Therefore,
∠ABO + ∠BOP = 180° (by interior angle Postulate)
118° + ∠BOP = 180°
∠BOP = 180° - 118°
∠BOP = 62°.... (1)
Since, ∠BOP + ∠POD = ∠BOD
Therefore, 62° + ∠POD = 152°
∠POD = 152° - 62°
∠POD = 90°.....(2)
∠POD + ∠ODC = 180° (by interior angle Postulate)
90° + ∠ODC = 180°
∠ODC = 180° - 90°