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laila [671]
2 years ago
6

Use the drop-down menu to complete the statement.

Mathematics
2 answers:
myrzilka [38]2 years ago
7 0

Answer:

4

Step-by-step explanation:

3\div\frac{3}{4}\\\\\frac{3}{1}*\frac{4}{3}\\ \\ 4

Juli2301 [7.4K]2 years ago
3 0
4
I already did the math btw
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Solve for x.<br><br> −14x+5=34<br><br> Enter your answer in the box
adelina 88 [10]
-14x + 5 = 34
-14x = 29
x = -2.10
7 0
3 years ago
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Plz help<br> PRE CALC !!!!!!!
sergey [27]

Answer:

I think it's the second one. 5.6487

Step-by-step explanation:

5 0
3 years ago
Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply. To begin conver
umka21 [38]

Answer:

1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.

Step-by-step explanation:

Let prove the validity of each choice:

1) To begin converting the equation to standard form, subtract 36 from both sides:

Let consider the following formula and perform the following algebraic operations:

(i) x^{2} + y^{2} + 4\cdot x - 6\cdot y  - 36 = 0 Given

(ii) x^{2} + 4\cdot x + y^{2} - 6\cdot y - 36 = 0 Commutative Property

(iii) (x^{2} + 4\cdot x + 4) - 4 + (y^{2} - 6\cdot y + 9) - 9 -36 = 0 Modulative/Associative Property/Additive Inverse Existence

(iv) (x+ 2)^{2} - 4 + (y - 3)^{2} - 9 - 36 = 0  Perfect Trinomial Square

(v) (x+2)^{2} +(y-3)^{2} = 4 + 9 + 36 Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property

(vi) (x+2)^{2} + (y-3)^{2} = 49 Definition of Addition/Result

False, to begin converting the equation to standard form, each side must be added by 36.

2) True, step (iii) on exercise 1) indicates that both side must be added by 4.

3) The general equation for a circle centered at (h, k) is of the form:

(x-h)^{2}+ (y-k)^{2} = r^{2}

Where r is the radius of the circle.

By direct comparison, it is evident that circle is centered at (-2,3).

True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).

4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).

5) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

6) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

5 0
2 years ago
Read 2 more answers
5x + 2y = -10<br> 3x + y = 66<br><br> please show work
liq [111]

Answer:

x=142, y=-360. (142, -360).

Step-by-step explanation:

5x+2y=-10

3x+y=66

----------------

5x+2y=-10

-2(3x+y)=-2*66

-----------------------

5x+2y=-10

-6x-2y=-132

-------------------

-x=-142

x=142

3(142)+y=66

426+y=66

y=66-426

y=-360

8 0
2 years ago
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1.) Distance formula<br> FIND THE DISTANCE BETWEEN THE PAIR OF POINTS
Vadim26 [7]

Answer:

A(x1,y1) and B(x2,y2)

Step-by-step explanation:

you take two points your start and your stop and put them into the equations and solve

3 0
3 years ago
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