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Drupady [299]
2 years ago
15

How to bypass securly or fortiguard (fortinet)

Computers and Technology
1 answer:
ira [324]2 years ago
3 0

Answer:

thanks for whatever you just said!! <3

Explanation:

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A researcher wants to do a web-based survey of college students to collect information about their sexual behavior and drug use.
Brilliant_brown [7]

Answer:

True.

Explanation:

An investigator would like to do an internet-based college student survey to gather data regarding their behavior as well as drug use. Even so, specific identifications are still not gathered and IP addresses might be available in the set of data. Damage threat must be assessed both by the magnitude (or severity) and the likelihood (or likelihood) of the hurt.

7 0
3 years ago
How Java provides protection through stack inspection approach ?
Natalija [7]
Pecting Java<span> 2's </span>stack inspection<span> policy to be enforced can-. not execute on .... Figure 2. PSLang security policy that </span>allows<span> at most 10 open windows. .... </span>Method<span> call/return: A → B. At start of B, look up</span>protection<span> domain PB for B's. code and push PB on the thread-local domain-. </span>Stack<span>. At return from B (either normally or by.</span>
3 0
3 years ago
Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv
elena-s [515]

Answer:

PART ONE

  1. import java.util.Scanner;
  2. public class CountToLimit {
  3.    public static void main(String[] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        int countLimit = 0;
  6.        int printVal = 0;
  7.        // Get user input
  8.        System.out.println("Enter Count Limit");
  9.        countLimit = scnr.nextInt();
  10.        do {
  11.            System.out.print(printVal + " ");
  12.            printVal = printVal + 1;
  13.        } while ( printVal<=countLimit );
  14.        System.out.println("");
  15.        return;
  16.    }
  17. }

PART TWO

  1. import java.util.Scanner;
  2. public class NumberPrompt {
  3.    public static void main (String [] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        System.out.print("Your number < 100: ");
  6.       int  userInput = scnr.nextInt();
  7.      do {
  8.           System.out.print("Your number < 100: ");
  9.           userInput = scnr.nextInt();
  10.       }while (userInput>=100);
  11.        System.out.println("Your number < 100 is: " + userInput);
  12.        return;
  13.    }
  14. }

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10

7 0
3 years ago
Why does a HTML seen to work even when its broken? why does the code sometimes turn pink?
OverLord2011 [107]

the reason HTML seems to work even if it has syntax errors is due to browser having built in ways to parse the code meaning it will still show but most likely look way different then you would want.

the code may turn pink due to syntax errors

5 0
3 years ago
A _____ object is the instance of a class that receives a request from another object. Select one: a. client b. server c. contra
creativ13 [48]

Answer:

b. server

Explanation:

A server serves responses to requests from client objects.

5 0
3 years ago
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