Data is?

4.3 mini programs AP computer science

allochka39001 [22]

1.

name = input("Enter your name: ")

num1 = int(input("Hello "+name+ ", enter an integer: "))

num2 = int(input(name+", enter another integer: "))

try:

if num1 % num2 == 0:

print("The first number is divisible by the second number")

else:

print("The first number is not divisible by the second number")

except ZeroDivisionError:

print("The first number is not divisible by the second number")

try:

if num2 % num1 == 0:

print("The second number is divisible by the first number")

else:

print("The second number is not divisible by the first number")

except ZeroDivisionError:

print("The second number is not divisible by the first number")

2.

import random, math

num1 = float(input("Enter a small decimal number: "))

num2 = float(input("Enter a large decimal number: "))

r = round(random.uniform(num1, num2), 2)

print("The volume of a sphere with radius " + str(r) + " is " + str(round(((4 / 3) * math.pi * (r ** 3)), 2)))

I hope this helps!

8 0

3 years ago

2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of

allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0

3 years ago

Explain the following terms as used in word processin

meriva

Answer:

A drop cap (dropped capital) is a large capital letter used as a decorative element at the beginning of a paragraph or section. The size of a drop cap is usually two or more lines.

a superscript is a character(s) half the height of a standard character and printed higher than the rest of the text.

In word processing, the word indent is used to describe the distance, or number of blank spaces used to separate a paragraph from the left or right margins.

6 0

2 years ago

What would happen without satellites???

laila [671]

Answer: without satellites there would be no way for the world to communicate

Explanation:

4 0

3 years ago

Read 2 more answers

Harvey is creating a presentation for his school project. He wants to have the same look on all the slides of his presentation.

Misha Larkins [42]

He should use PowerPoint and the design should be feathered

8 0

3 years ago