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Licemer1 [7]
3 years ago
5

A 1 kg block of iron sits outside in the direct sun from 8am to 10am. At 8am the temperature of the block was 20.0°C and at 10am

the temperature of the block was 27.5°C.
How much heat did the block of Iron absorb from the sun?
use q=mcΔT
Chemistry
1 answer:
Julli [10]3 years ago
8 0

Answer:

About 3.5 kJ.

Explanation:

Recall the heat transfer equation:

\displaystyle q = mC\Delta T

Where <em>q</em> is the heat; <em>m</em> is the mass of the substance; <em>C</em> is its specific heat; and Δ<em>T</em> is the change in temperature.

The given specific heat of iron is 462 J/kg -°C.

Substitute and evaluate. Ensure correct units:
\displaystyle \begin{aligned} q & = (1\text{ kg})\left(\frac{462\text{ J}}{\text{kg -$^\circ$C}}\right)(27.5\text{ $^\circ$C} - 20.0\text{ $^\circ$C}) \\ \\ & = (1\text{ kg})\left(\frac{462\text{ J}}{\text{kg -$^\circ$C}}\right)(7.5\text{ $^\circ$C}) \\ \\  & = 3.5\times 10^3 \text{ J} = 3.5\text{ kJ}\end{aligned}

Therefore, the block of iron absorbed about 3.5 kJ of heat.

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3 years ago
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sashaice [31]

Answer:

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Explanation:

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3 years ago
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4 years ago
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Answer:

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