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stiv31 [10]
2 years ago
11

What do alkali metals react bad with

Chemistry
2 answers:
solmaris [256]2 years ago
6 0

Explanation:

what do you mean by "bad"

Setler79 [48]2 years ago
6 0

Answer:Alkali metals react with water to produce heat, hydrogen gas, and the corresponding metal hydroxide. The heat produced by this reaction may ignite the hydrogen or the metal itself, resulting in a fire or an explosion. The heavier alkali metals will react more violently with water.

Explanation:

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A balloon contains a 10% glucose solution. The balloon is permeable to water but not to glucose. A beaker contains a 5% glucose
deff fn [24]

The state of the balloon:

When the balloon is submerged in the beaker, the amount of water in the beaker will get reduced.  

What is Osmosis:    

Based on the concentration of solutes on both sides of the membrane, water will flow through a permeable membrane in a specific direction.

<u><em>Hypertonic solution:</em></u>

It means that there are more solutes present in the surrounding environment than in the cell itself.

<u><em>Hypotonic solution:</em></u>

In a hypotonic solution, the concentration of solutes inside the cell is higher than that outside the cell.

  • When comparing two solutions, the one with the larger solute concentration is hypertonic, and the one with the lower solute concentration is hypotonic. Isotonic solutions have an identical solute concentration.

  • While the solution in the beaker is hypertonic, Meaning that will draw water molecules out of the cell. As water molecules move from a location of high water potential (dilute solution) to a region of reduced water potential (10% glucose solution), the water from the 5% glucose solution will flow into the 10% one (concentrated solution)
  • This is the reason why the amount of water decreases when the balloon is submerged in the beaker.

Learn more about the glucose solution and permeability here,

brainly.com/question/14748422

#SPJ4

 

 

 

 

7 0
2 years ago
A 33.0 mL sample of 1.15 M KBr and a 59.0 mL sample of 0.660 M KBr are mixed. The solution is then heated to evaporate water unt
Oksi-84 [34.3K]

Answer:

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

Explanation:

<u>Step 1:</u> Data given

Sample 1: The 1.15 M sample  has a volume of 33.O mL

Sample 2: The 0.660 M sample has a volume of 59.0 mL

Molar mass of KBr = 119 g/mol

Molar mass of AgNO3 = 169.87 g/mol

<u>Step 2:</u> Calculate number of moles for both samples

Number of moles = Molarity * Volume

Sample 1:  1.15 M * 33 *10^-3 L = 0.03795 moles

Sample 2: 0.660 M *59*10^-3 L = 0.03894 moles

Total mol KBr = 0.03795 + 0.03894 = 0.07689 moles

<u>Step 3:</u> Calculate total mass

mass = Number of moles * Molar mass

mass = 0.07689 moles * 119 g/moles = 9.15 grams  ( in 55mL)

<u>Step 4</u>: Calculate moles of AgBr

AgNO3 reacts with KBr  

KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq)

1 mole of KBr consumed, needs 1 mole of AgNO3 to produce 1 mole of AgBr and 1 mole of KNO3

So 0.07689 moles of KBr wll need 0.07689 moles of AgNO3

<u>Step 5:</u> Calculate mass of silver nitrate

mass of AgNO3 = Moles of AgNO3 * Molar mass of AgNO3

mass of AgNO3 = 0.07689 moles * 169.87 g/mol = 13.06 grams

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

8 0
3 years ago
What is density? A) mass divided by volume B) volume divided by mass
wolverine [178]

Answer:

A) mass divided by volume

Explanation:

7 0
3 years ago
Read 2 more answers
When an aqueous solution of silver nitrate is
Andre45 [30]

Answer:

K^{+} and NO_{3}^{-}

Explanation:

The equation for the reaction is AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

With all the ions, it is

Ag^{+}(aq) + NO_{3} ^{-}(aq) + K^{+}(aq) + Cl^{-}(aq)  ==> AgCl(s) +

K^{+} and NO_{3} ^{-} do not change, so they are the spectator ions and are removed

The ionic equation is:

Ag^{+}(aq) + Cl^{-}(aq) ==> AgCl(s)

8 0
3 years ago
4 examples of Substances that sublime?
AVprozaik [17]

1. Dry Ice (solid carbon dioxide)

2. Iodine

3. Arsenic

4. Naphthalene

3 0
4 years ago
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