Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide,
Explanation:
The reaction equation for given reaction is as follows.
Here, 1 mole of reacts with 3 moles of .
As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide is 152 g/mol.
Number of moles is the mass of substance divided by its molar mass. So, moles of is calculated as follows.
Now, moles of .given by 0.5 mol of is calculated as follows.
As molar mass of is 2.016 g/mol. Therefore, mass of is calculated as follows.
Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, .
Answer:3 moles
Explanation:
For every three molecules of CO2 that enters the Calvin cycle, one molecule of the three carbon glyceraldehyde 3-phosphate (G3P) is produced. Two molecules of G-3-P are required to produce one molecule of glucose. Therefore, the Calvin cycle needs to make a total of 6 turns to produce two molecules of G-3-P.
Answer:
P₂ = 0.11 atm
Explanation:
Given data:
Initial pressure = 0.12 atm
Initial temperature = 294 K
Final pressure = ?
Final temperature = 273 K
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.12 atm / 294 K = P₂/273 K
P₂ = 0.12 atm × 273 K / 294 K
P₂ = 32.76 atm. K /294 K
P₂ = 0.11 atm
Answer:
A
Explanation:
I think this is true letter a
There had been new discoveries of chemicals that have been added to the periodic table in recent years