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OverLord2011 [107]

3 years ago

10

Given that log Cart 2) + log, b=0 and ing (a-2) 16g, b=actl Show = "feetfiad Metult possible velers of a cand is where a, b er (

a that 92 442480 an 2 it soln

1 answer:

Murljashka [212]3 years ago

4 0

Answer:

12+12 log2) b=34) 54+90)=10000+32+54=9000

Step-by-step explanation:

I know the answer I am a math tutor at Elomantry High Scholl Teaching for 6 years now

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A management company opens a large apartment complex in anticipation of growth in the community. The company compiles statistics

bezimeni [28]

The equation is given to us in slope intercept form. -34.85 is the slope and the y-intercept is 938.

Therefore, we can say:
The rate of change for the line of best fit is -34.85 which represents the decrease in number of available apartments per week since the complex opened.
The y-intercept is 938 which represents the number of apartments when it first opened.

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3 years ago

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gladu [14]

Answer:

b. Multiply 15 by 9, then divide by 2

Step-by-step explanation:

15 / 2/9 = 15 * 9/2

Answer: b. Multiply 15 by 9, then divide by 2

6 0

3 years ago

Here are three statements about the daily low temperatures for the 2 cities.

Maslowich

Answer:

Step-by-step explanation:

6 0

4 years ago

<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{

Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative

$-2$ -> neagtive

$-1\leq x$ -> neagtive

$x>2$ -> positive

Therefore, the solution to the inequality is the following;

$x>2$

6 0

3 years ago

Graph g(x)=2cos x. Use 3.14 for pi

oksian1 [2.3K]

Sry im not 100% sure, but i think it's suppose to look like this on a graph.

3 0

3 years ago