$\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}~~ \begin{cases} s=side's\\ \qquad length\\ \cline{1-1} s = 8 \end{cases}\implies A=\cfrac{8^2\sqrt{3}}{4}\\\\\\ A=16\sqrt{3}\implies A\approx 24.71$

6 0

3 years ago

Solve for b in: (2B/x)-Q=Z

andrezito [222]

Answer:

B = (zx/2)+ (qx/2)

Step-by-step explanation:

7 0

3 years ago

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Mr. Stanford’s greenhouse has the dimensions shown. The volume of the greenhouse is 90 cubic yards. Find the missing dimension o

bulgar [2K]

Answer:

$h=10\ yd$

Step-by-step explanation:

we know that

The volume of the triangular prism of the figure is equal to

$V=Bh$

where

B is the area of the triangular base

h is the height of the triangular prism

Find the value of B

$B=\frac{1}{2}(6)(3)=9\ yd^{2}$

we have that

$V=90\ yd^{3}$

substitute the values and solve for h

$90=9h$

$h=90/9=10\ yd$

5 0

3 years ago

HELPPP <br><br> Solve for b 2 in A = h(b 1+b 2), if A = 16, h = 4, and b 1 = 3.<br><br> b 2 =

Lilit [14]

Answer:1

Step-by-step explanation: substitute all the corresponding terms so you get, 16=4(3+b2)

Then you multiply and get 16=12+4b2 then subtract 12 from both sides to get 4=4b2 and then divided both sides by 4 and you get 1=b2

6 0

2 years ago

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