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umka2103 [35]
3 years ago
6

Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0
Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }

The magnitude of vecor v is given to be 10. So we can write:

10= \sqrt{ (-1-x)^{2} + (5-y)^{2} } \\ \\ 100=(-1-x)^{2} + (5-y)^{2}

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector. 

The point in option d, satisfies the equation.

100=(-1+7)^{2} +(5+3)^{2}  \\  \\ 
100=36+64 \\  \\ 
100=100

Thus, the answer to this question is option D
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The equation tan(55 degree) equals StartFraction 15 Over b EndFraction can be used to find the length of Line segment A C. Trian
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The length of line segment BC is 10.5 inches.

Given that

The equation tan(55 degrees) equals 15/b, which can be used to find the length of Line segment AC.

Triangle ABC is shown.

Angle BCA is a right angle and angle BAC is 55 degrees.

The length of AC is b and the length of hypotenuse BC is 15 centimeters.

We have to determine

What is the length of Line segment AC?

According to the question

Triangle ABC is shown.

Angle BCA is a right angle and angle BAC is 55 degrees.

The length of AC is b and the length of hypotenuse BC is 15 centimeters.

Here, BC is not the hypotenuse of the right triangle ABC.

The length line segment AC is given by,

In triangle ABC

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Where \rm tan\theta = 55 degrees, Perpendicular = 15 and base is b.

Substitute all the value in the equation

\rm Tan\theta = \dfrac{Perpendicular}{Base}\rm\\\\ Tan55= \dfrac{15}{b}\\\\b = \dfrac{15}{Tan55}\\\\b = \dfrac{15}{1.42}\\\\b = 10.5 \ inches

Hence, the length of line segment BC is 10.5 inches.

To know more about Trigonometry click the link given below.

brainly.com/question/13350002

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