Let the digit in the tens place be x
tens place = x (therefore the value is 10x)
ones place = x + 7
The number is 10x + x + 7
Add 26 to it
10x + x + 7 + 26 = 11x + 33
It is 5 times the sum of the digit
11x + 33 = 5(x + x + 7)
11x 33 = 10x + 35
x = 2
x+ 7 = 2 + 7 = 9
So the number is 29
Answer:
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Answer:
1. d 2. d 3. a
Step-by-step explanation:
1. factor
((w-4)(w-6))/((w-5)(w-6))+8/(w-5)
solve
(w-4)/(w-5)+8/(w-5)
(w+4)/(w-5), so d
2.factor
((b+2)(b-4))((b+2)(b-1))-6/(b-1)
solve
(b-4)/(b-1)-6(b-1)
(b-10)/(b-1), so d
3. (2/5t-3/3t)/(1/2t+1/2t)
(2/5t-1/t)/(2/2t)
(2/5t-1/t)/(1/t)
t(2/5t-1/t)
2/5-1=-3/5, so a
Answer:
3813.6
Step-by-step explanation:
90.8 x 42 = 3813.6
