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3 years ago

Find the cost of the following item. A table marked up $45.00, selling for $189.95 4.22 144.95 234.95 8,357.80

Mathematics

2 answers:

natita [175]3 years ago

7 0

Answer:

Cost price of an item = $144.95

Step-by-step explanation:

Cost price is the price at which the article is purchased .

It includes all the expenses incurred on that item till the time it is owned by us .

Selling price is the price at which the item is sold to the customer .

Market price is the price marked on the product . It is basically the current price of the item .

We know that selling price - market price = cost price

Given :

Market price of an item = $45.00

Selling price of an item = $189.95

To find : cost price of an item

Solution :

Cost price = $189.95 - $45.00 = $144.95

Artemon [7]3 years ago

4 0

Subtract:
189.95 - 45.00 = 144.95

the cost = 144.95

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo

nlexa [21]

Given:

Equation of line $7x-4y=-12$ .

To find:

The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

$7x-4y+12=0$

Slope of line is

$\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{7}{(-4)}$

$m_1=\dfrac{7}{4}$

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

$m_1m_2=-1$

$m_2=-\dfrac{1}{m_1}$

$m_2=-\dfrac{4}{7}$ $[\because m_1=\dfrac{7}{4}]$

Now, the slope of perpendicular line is $m_2=\dfrac{4}{7}$ and it goes through (-21,2). So, the equation of line is

$y-y_1=m_2(x-x_1)$

$y-2=-\dfrac{4}{7}(x-(-21))$

$y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)$

$y-2=-\dfrac{4}{7}x-12$

$y=-\dfrac{4}{7}x-12+2$

$y=-\dfrac{4}{7}x-10$

Therefore, the required equation in slope intercept form is $y=-\dfrac{4}{7}x-10$ .

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Answer:

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Step-by-step explanation:

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