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Ksivusya [100]
2 years ago
12

Choose the letter of the equation from the drop down

Mathematics
1 answer:
UNO [17]2 years ago
5 0

After comparing with standard equations of the ellipse and hyperbola, we will get the center of the ellipse and hyperbola.

<h3>What is hyperbola?</h3>

It's a two-dimensional geometry curve with two components that are both symmetric. In other words, the number of points in two-dimensional geometry that have a constant difference between them and two fixed points in the plane can be defined.

Here the equation of the ellipse and hyperbola are not given.

As we know, the standard form of the ellipse:

\rm \dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1

Here (h, k) is the center of the ellipse.

If we compare with the standard equation center, we will get ellipse center.

The standard form of the hyperbola equation:

\rm \dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2} = 1

Here (h, k) is the center of the hyperbola.

Thus, after comparing with standard equations of the ellipse and hyperbola, we will get the center of the ellipse and hyperbola.

Learn more about the hyperbola here:

brainly.com/question/12919612

#SPJ1

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Find the value of x. <br><br> A. 10 <br> B. 15 <br> C. 20 <br> D. 25
Ira Lisetskai [31]

Answer:

(5x+13)+(3x+7)=180°

5x+3x=180°-7°-13°

8x=160°

x=160/8

x=20°

option C is correct

6 0
3 years ago
Find the greatest common factor: 24y^8 + 6y^6
Marrrta [24]

Find the Greatest Common Factor (GCF)

<u>GCF = 6y^6</u>

Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)

6y^6(24y^8/6y^6 + 6y^6/6y^6)

Simplify each term in parenthesis

<u>6y^6(4y^2 + 1)</u>

7 0
3 years ago
7) what is the BEST conclusion we can draw from the graph <br><br> (the answers are in the picture)
Viktor [21]

Answer:

a

Step-by-step explanation:

7 0
3 years ago
Please help me!!!!!!! It's very important!!!!
qwelly [4]
You could just use 3.14 or 22/7
6 0
3 years ago
Suppose △PKN≅△BGH△PKN≅△BGH. Which other congruency statements are correct? Select each correct answer. △NKP≅△HBG△NKP≅△HBG △KPN≅△
NeTakaya

Answer:

△NPK≅△HBG; and △KNP≅△GHB

Explanation:

Using the given congruence statement, we can determine corresponding pieces of the triangles:

P corresponds to B; K corresponds to G; and N corresponds to H.

This means that △NKP≅△HGB, not HBG.

△KPN≅△GBH, not BHG.

△NPK≅△HBG; this is correct.

△KNP≅△GHB; this is correct.

8 0
3 years ago
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