Add 1, then add 2, then add 3, then 4, then 5, then 6.
Answer:
Second option: 81y^4 - 16x^2, the difference of squares
Step-by-step explanation:
(9y^2-4x)(9y^2+4x) is a special product named difference of squares, then we can apply this formula:
(a-b)(a+b)=a^2-b^2, with a=9y^2 and b=4x, then:
(9y^2-4x)(9y^2+4x)=(9y^2)^2 - (4x)^2
(9y^2-4x)(9y^2+4x)=(9)^2 (y^2)^2 - (4)^2 (x)^2
(9y^2-4x)(9y^2+4x)=81y^(2*2) - 16x^2
(9y^2-4x)(9y^2+4x)=81y^4 - 16x^2
Answer: uuf, hard
Step-by-step explanation: SORRY, DON'T KNOW
Answer:
(A) 2^{5} * 5 * 7
Step-by-step explanation:
Your question formatting made it very complicated to understand the possible answers. Please use some notation or the equation editor next time.
So, the exponential form a way to write a number using multiplications and powers.
Let's examine the various options (if I read them correctly)
(A) 2^{5} * 5 * 7 - YES!
2^{5} is 32, so 32 * 5 * 7 = 160 * 7 = 1120
(B) 5² · 8 - NO
= 25 * 8 = 200
(C) 2² * 5³ * 7 - NO
= 4 * 125 * 7 =500 * 7 = 3500
(D) 2 · 5 · 7 - NO
= 10 * 7 = 70
