2x-11=7x+9
i would bring the -11 over to the 9. change it to 9+11. the equation is now
2x=7x+9+11
2x=7x+20
then bring the 7x over chaning it to -7x so then it is
2x-7x=20
-5x=20
then divide by -5
-5x/-5=20/-5
answer is
x=-4
Answer:
C. 0.305
Step-by-step explanation:
100 - 39 = 61
.5 x .61 = .305
30.5%
To get rid of
, you have to take the third root of both sides:
![\sqrt[3]{x^{3}} = \sqrt[3]{1}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20)
But that won't help you with understanding the problem. It is better to write
as a product of 2 polynomials:
From this we know, that
is the solution. Another solutions (complex roots) are the roots of quadratic equation.
You have the lenght that is 3w, so lenght is the third part and the width the first part.
You assign the value 3 to l and the value 1 to w
Of course, you have to do the "semiperimeter" or you'll get double sides.
Semiperimeter = 26/2 = 13 ft.
You sum the parts
3+1 = 4
13/4 = 3,25 ft. (1 part)
3,25*1 = 3,25 ft. (Widht)
3,25*3 = 9,75 ft. (Lenght)
You can solve it even as an equation
You put x the lenght, the width is 3x
x+3x = 13
4x = 13
x = 3,25
w = 3*3,25 = 9,75
=>2|x+3|<-5+17
=>2|x+3|<12
=>|x+3|<12/2
=>x+3<12/2 or x+3>-12/2
=>x<6-3 or x>-6-3
=>x<3 or x>-9
Thus
x belongs the the interval [-9,3]
