4. In aliens, skin color is a codominant trait. What skin color will the offspring of the following parents have?

BaO2 is a peroxide. Why?

melamori03 [73]

Answer:

jajjsjsjddjdjdjdjdjjdjeieiririitofodoslwnridooskemridisoskswkwjj jwjwiwiwiwkiwiw

7 0

3 years ago

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The diagram below shows the energy conversions of the Krebs cycle, which is part of cellular respiration. The U-shaped

VLD [36.1K]

Answer:

i dont even know tbh jk i wont waste ur time unless nvm ok so the answer is The correct answer would be C.10. Krebs cycle is a part of cellular respiration that takes place in the mitochondria. Five energy conversions take place in one complete cycle of the Krebs cycle. These conversions lead to the formation of three molecules of NADH, one molecule of FADH₂ and one molecule of ATP.

Explanation:bc im superrr smart

8 0

3 years ago

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The emission spectrum of cesium contains two lines whose frequencies are (a)

Lady bird [3.3K]

The lines are violet and blue respectively.

<h3>What is the energy?</h3>

We know that the energy of the photon could be obtained by the use of the equation;

E = hf

E = energy

h = Plank's constant

f = frequency

For the first line;

E = 6.6 * 10^-34 Js * 3.45 x 10^14 Hz = 2.3 * 10^-19 J

Given that;

E = hc/λ

λ = hc/E

λ = 6.6 * 10^-34 * 3 * 10^8/2.3 * 10^-19

λ = 8.61 * 10^-7 m or 861 nm

The color is violet

For the second line;

E = 6.6 * 10^-34 Js * 6.53 xx 10^14 Hz

E = 4.3 * 10^-19 J

E = hc/λ

λ = hc/E

λ = 6.6 * 10^-34 * 3 * 10^8/4.3 * 10^-19

λ = 4.60 * 10^- 7 m or 460 nm

The color is blue

Learn more about emission spectrum:brainly.com/question/13537021

#SPJ1

8 0

2 years ago

PLEAAAASE HELP CHEM

alukav5142 [94]

Answer:

5. +5

6. +7

Explanation:

The oxidation state can be obtained as follow:

5. Oxidation state of oxygen, O = –2

Oxidation state of phosphorus, P =?

P3O10 = –5

3P + 10O = –5

3P + (10 x –2) = –5

3P – 20 = –5

Collect like terms

3P = –5 + 20

3P = 15

Divide both side by 3

P = 15/3

P = +5

Therefore, the oxidation state of P in P3O10^5- is +5

6. Oxidation state of oxygen, O = –2

Oxidation state of manganese, Mn =.?

Mn2O7 = 0

2Mn + 7O = 0

2Mn + (7 x –2) = 0

2Mn – 14 = 0

Collect like terms

2Mn = 14

Divide both side by 2

Mn = 14/2

Mn = +7

Therefore, the oxidation state of Mn in Mn2O7 is +7

4 0

3 years ago

The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for t

kotykmax [81]

Answer:

B

Explanation:

We are given that ammonia can be produced from hydrogen gas and nitrogen gas according to the equation:

$\displaystyle 3\text{H$_2$} + \text{N$_2$} \longrightarrow 2\text{NH$_3$}$

We want to determine the mass of hydrogen gas that must have reacted if 0.575 g of NH₃ was produced.

To do so, we can convert from grams of NH₃ to moles of NH₃, moles of NH₃ to moles of H₂, and moles of H₂ to grams of H₂.

We are given that the molar masses of NH₃ and H₂ are 17.03 g/mol and 2.0158 g/mol, respectively.

From the equation, we can see that two moles of NH₃ is produced from every three moles of H₂.

With the initial value, perform dimensional analysis:

$\displaystyle \begin{aligned} 0.575\text{ g NH$_3$}& \cdot \frac{1\text{ mol NH$_3$}}{17.03\text{ g NH$_3$}} \cdot\frac{3\text{ mol H$_2$}}{2\text{ mol NH$_3$}} \cdot \frac{2.0158\text{ g H$_2$}}{1\text{ mol H$_2$}} \\ \\ & = 0.102\text{ g H$_2$}\end{aligned}$

*Assuming 100% efficiency.

Our final answer should have three significant figures. (The first term has three, the second term has four (the one is exact), the third term is exact, and the fourth term has five. Hence, the product should have only three.)

In conclusion, our answer is B.

3 0

3 years ago