Question

A student carefully placed 15.6 g of sodium in a reactor supplied with chlorine gas. When the reaction was complete, the student obtained a 39.7 g sample of sodium chloride. How many grams of chlorine gas reacted?

Answer 1

Answer:

24.09 grams of chlorine gas reacted.

Explanation:

$2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

Moles of sodium chloride = $\frac{39.7 g}{58.5 g/mol}=0.6786 mol$

According to reaction, 2 moles of  NaCl are formed from 1 mole chlorine gas.

Then 0.6786 moles of NaCl will be formed from;

$\frac{1}{2}\times 0.6786 mole=0.3393 mol$

Mass of 0.3393 moles of chlorine  gas:

0.3393 mol × 71 g/mol = 24.09 g

24.09 grams of chlorine gas reacted.