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Vanyuwa [196]
3 years ago
6

Python's ____ mechanism allows the programmer to view an interface for an entire class or an individual method, at the shell pro

mpt.
Computers and Technology
1 answer:
eduard3 years ago
8 0

The question above has multiple choices as follows;

a. API

b. docstring

c. help

d. man

Well, I am stuck between B and C. I’ll however settle for (B) docstring.


Python docstrings provide an easier way to associate documentation with python classes, modules and functions. The interactive help function on the other is built in and is intended for interactive use. This function exists to view help interactively. With the help feature, you can quickly learn classes, modules, functions and many more.






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WooW We Have To All This Which Class can you Please tell

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A network with 6 bits remaining for the host portion will have how many usable hosts?​
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Some programmers include scroll bars, title bars, buttons, and menus in a program simply by adding them to a layout through a pr
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Visual.

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a problem exists when the current condition differs from a desired condition. This idea defines which step in problem-solving?
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Read 2 more answers
g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err
grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

   

   // variables declared

   int n;

   int sum=0;

   float avg;

   

   do

   {

       // user input taken for number    

       cout<< "Enter a number between 1 and 100 (inclusive): ";

       cin>>n;

       

       if(n<1 || n>100)

           cout<<" Number is out of range. Enter valid number."<<endl;

       

   }while(n<1 || n>100);

   

   cout<<" "<<endl;

   

   // printing even numbers between num and 50  

   for(int num=1; num<=n; num++)

   {

       sum = sum + num;

   }

   

   avg = sum/n;

   

   // displaying sum and average

   cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

   cout<<"Average of numbers between 1 and "<<n<<" is ";

   printf("%.2f", avg);

   

       return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

 

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0
3 years ago
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