Answer:
Answered below
Explanation:
aFile = open("books.txt", "r")
This code uses the function open() which takes two parameters. The first parameter is the file name while the second parameter is the mode in which you are accessing the file.
The "r" mode opens the file in a reading state. That is, you can only read from the file. This code completes the reading process
aFile.read( )
The "w" mode opens the file so you can write to it and make changes.
The "a" mode opens the file so you can add contents to it.
Mixed Reality expand on Augmented Reality option d: by enabling real-time interaction between real and virtual objects.
<h3>How does mixed reality expand on augmented reality?</h3>
Mixed reality is known to be one that is made up of both augmented reality and that of augmented virtuality.
Note that Mixed reality is one that acts so as to make an environment with interactive kinds of digital objects. Augmented reality needs a screen to be able to experience the augmented experience. Mixed reality is said to be experienced via the a headset.
Hence, Mixed Reality expand on Augmented Reality option d: by enabling real-time interaction between real and virtual objects.
Learn more about Augmented Reality from
brainly.com/question/9054673
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You should follow a set of directions
The importance of a good work ethic in school and life. Your good work ethic tells future employers what they might expect from you on the job.
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
