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2 years ago

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Given a trapezoid with a height of 4.3m and bases of 9.2 m and 3.2m, what is the area of the trapezoid? Do not include units in

your answer.

1 answer:

77julia77 [94]2 years ago

7 0

For a height of 4.3m and bases of 9.2 m and 3.2m, the area of the trapezoid is mathematically given as

A=26.7

<h3>What is the area of the trapezoid?</h3>

Generally, the equation for the trapezoid is mathematically given as

A=0.5*(a+b)*h

Therefore

A=0.5*(3.2+9.2)*4.3

A=26.7

In conclusion,area of the trapezoid

A=26.7

Read more about Arithmetic

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Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

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Part 2) we know that

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$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

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$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

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