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kherson [118]
3 years ago
11

FeCl3 + O2  Fe2O3 + Cl2 BALANCE the equation

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0
4 miles of FeCl3 x (6 Cl2 / 4 FeCl3)=6 moles Cl2 ( Yahoo )
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Question 4: The storage in a reach of a river at a point in time is 255 m3 (meters cubed) . Determine the average rate of inflow
irakobra [83]

Answer:

0.319 m³/s

Step-by-step explanation:

Data provided:

Initial volume in the river = 255 m³

Final volume required in the storage = 325 m³

Average outflow = 0.30 m³/s

Duration for raising the level = 1 hour = 3600 seconds

Now,

The actual volume required to raise the volume to 325 m³

= Final volume - Initial volume

= 325 m³ - 255 m³

= 70 m³

also,

the amount of outflow in 1 hour = Average rate of outflow × Time

= 0.30 m³/s × 3600 s

= 1080 m³

Therefore,

the total volume required = 1080 m³ + 70 m³ = 1150 m³

Now,

the average rate of inflow required = \frac{\textup{Total volume required}}{\textup{Time}}

= \frac{\textup{1150}}{\textup{3600}}

= 0.319 m³/s

8 0
3 years ago
Kamal wrote the augmented matrix below to represent a system of equations
Alina [70]

Consider the operation is R_2\to -3R_2.

Given:

The augmented matrix below represents a system of equations.

\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]

To find:

Matrix results from the operation R_2\to -3R_2.

Step-by-step explanation:

We have,

\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]

After applying R_2\to -3R_2, we get

\left[\left.\begin{matrix}1&0&1\\-3(1)&-3(3)&-3(-1)\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-3(-9)\\-2\end{matrix}\right]

\left[\left.\begin{matrix}1&0&1\\-3&-9&3\\3&2&0\end{matrix}\right|\begin{matrix}-1\\27\\-2\end{matrix}\right]

Therefore, the correct option is A.

7 0
3 years ago
Domain and Range...
Veseljchak [2.6K]

The domain is the X values and the range is the y values.

The blue line starts at X 0 and Y 0 and moves up and to the right.

This means the range and domain are equal to or greater than 0.

The 3rd choice is the correct one.

3 0
3 years ago
a rectangular parking lot has an area of 7/10 square kilometer the width is 1/3 kilometer what is the length of the parking lot
Virty [35]

Answer:

2\frac{1}{10} km

Step-by-step explanation:

We are given;

  • The are of a rectangle as 7/10 km²
  • Width of the rectangle is 1/3 km

We are required to find the length of the rectangle;

We need to know how to find the area of a rectangle first;

Area of rectangle = Length × Width

Rearranging the formula;

Length = Area of rectangle ÷ Width

            = 7/10 km² ÷ 1/3 km

   We get;

           =\frac{7}{10} *\frac{3}{1}

           =\frac{21}{10}

           =2\frac{1}{10} km (improper fraction)

Thus, the length of the rectangular park is 2\frac{1}{10} km

5 0
3 years ago
What is the difference in 2/8 and 1/2
prohojiy [21]

Answer:

1/4

Step-by-step explanation:

2/8 is 1/4 and 1/2 is 2/4, subtract and you get 1/4.

4 0
3 years ago
Read 2 more answers
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