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3 years ago

FeCl3 + O2  Fe2O3 + Cl2 BALANCE the equation

Mathematics

1 answer:

Tomtit [17]3 years ago

3 0

4 miles of FeCl3 x (6 Cl2 / 4 FeCl3)=6 moles Cl2 ( Yahoo )

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The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra

kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

$p-50 = \dfrac{50-52}{4000-3800}(x - 4000)$

$p-50 = \dfrac{-2}{200}(x - 4000)$

$p-50 = \dfrac{-x}{100}+ 40$

$p = \dfrac{-x}{100}+ 90$

R(x) = x . p

$R(x) = x (\dfrac{-x}{100}+ 90)$

$R(x) = \dfrac{-x^2}{100}+ 90x)$

$\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))$

$\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)$

at $\dfrac{d}{dx}(R(x)) = 0$

$\dfrac{-2x}{100}= -90$

x = 4500

$\dfrac{d^2}{d^2x}(R(x)) = -ve$

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

$p = \dfrac{-4500}{100}+ 90$

p = $45

6 0

4 years ago

Simplify.<br> 6² + 3²<br> 09<br> O 18<br> O 45<br> 081

swat32

Answer:

Step-by-step explanation:

6² + 3²

36 + 9

Follow me please

4 0

3 years ago

PLEASE HELP!!!!!!WILL GIVE BRAINLIEST

Dmitry [639]

Answer:

The angles do not share a special relationship.

Step-by-step explanation:

Angles 13 — 20 are right angles. Angle 12 is complementary to given angle 7, so is 90°-72° = 18°. Angle 10 is vertical with angle 12, so is also 18°.

There is no special relationship between right angle 14 and acute angle 10.

7 0

3 years ago

What is the sum of 4 1/12 + (-5 1/3)?

MAVERICK [17]

-5/6. Hope this helps.

8 0

3 years ago

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Which is a true statement comparing the graphs of x^2/3^2 - y^2/4^2= 1 and y^2/3^2 - x^2/4^2 = 1?

laila [671]

Answer: B) The lengths of both transverse axes are the same.

Step-by-step explanation: Given Hyperbola equations :

$\frac{x^2}{3^2}-\frac{y^2}{4^2}=1$ and

$\frac{y^2}{3^2}-\frac{x^2}{4^2}=1$

First one : $\frac{x^2}{3^2}-\frac{y^2}{4^2}=1$ is a Horizontal Hyperbola.

a = 3 and 2a = 6.

Length of transverse axis = 6.

And second one : $\frac{y^2}{3^2}-\frac{x^2}{4^2}=1$ is a Vertical Hyperbola.

b=3 and 2b = 6

Length of transverse axis = 6.

The lengths of both transverse axes are the same.

Therefore, correct option is B option :

<h3>The lengths of both transverse axes are the same.</h3>

3 0

4 years ago

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