Answer:
<h2>Number of solutions: 3</h2><h2>Type: -10, -2, 2.8</h2>
Step-by-step explanation:
f(x) = 0 - the solutions are the x-intercepts.
Look at the picture.
<em>Unit: 2 : 5 = 0.4</em>
The correct answer for this question is this one: 5 / 7
<span>There exists the same question from other source that has the continuation of the problem. <em>Use proportions to test your measurements and see if they match this ratio. Height is 5ft</em>
So this how to solve this:
Set the equation as:
7x = 5
x = 5 / 7</span>
9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
Y=36
it basically says y=(9-3)^2
which is y=6^2
which is then y=36
I got x=2.64 or x=1.32 i don't know if i done it right