Let the total toys be x.
The first has (1/10)x = x/10
The third child has one more toys than the first = x/10 + 1
The fourth has double of the third: = 2* (x/10 + 1) = 2x/10 + 2
Since we know that the second child has 12 more toys than the first
Therefore the Second minus First = 12.
First let us find the second.
1st + 2nd + 3rd + 4th = x
x/10 + 2nd + (x/10 + 1) + (2x/10 + 2) = x
2nd + x/10 + x/10 + 1 + 2x/10 + 2 = x
2nd + x/10 + x/10 + 2x/10 + 1 + 2 = x
2nd + 4x/10 + 3 = x
2nd = x - 4x/10 - 3
2nd = 6x/10 - 3
But recall
2nd - 1st = 12
6x/10 - 3 - x/10 = 12
6x/10 - x/10 = 12 + 3
5x/10 = 15
5x = 15 * 10
x = 15*10 /5
x = 30
So there were 30 toys in all.
<h3>
Answer: 6</h3>
Explanation:
List list the multiples of each value
- multiples of 2 = {2, 4, 6, 8, 10, ...}
- multiples of 3 = {3, 6, 9, 12, 15, ...}
- multiples of 6 = {6, 12, 18, 24, ...}
In each list, we see 6 show up. This is the smallest multiple that is in common; therefore, the LCM is 6
Side note: The LCM is useful to help add and subtract fractions.
C = 2pi r= 2 (3.14) (27) = 169.56
Let XY = x
169.56 / 360 = x / 60
360x = 169.56 * 60
360x = 10173.60
x = 28.26
x = 28.3
Answer is C. 28.3 cm
"A quadrilateral with both pairs of opposite sides parallel and all sides the same length, i.e., an equilateral parallelogram."
You will pay $533.75 total. $<span>33.75 being the sales tax</span>