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2 years ago

Is a parallelogram an equilateral?

1 answer:

4 0

"A quadrilateral with both pairs of opposite sides parallel and all sides the same length, i.e., an equilateral parallelogram."

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Simplify this expression. 20.25 – 9 + 11 о 1 4 0 18.75 0 21? 0 40.75

Greeley [361]

Answer:

$21\frac{3}{4}$

Step-by-step explanation:

Step 1: Add the numbers.

20.25 can also be expressed as $20\frac{1}{4}$ , because $\frac{2025}{100}$ = $\frac{81}{4}$ = $20\frac{1}{4}$ . So if we add $20\frac{1}{4}$ and 11, we would get $31\frac{1}{4}$

Step 2: Solve

$31\frac{1}{4} -9\frac{1}{2}$

Subtract the whole numbers

$31-9=21$

Combine the fractions

This means addition. Also, since our denominators are not the same value, we have to find the LCM (Least Common Denominator): What do 2 and 4 have in common that they can divide themselves by? 4. We know this because 2 divided by 4 is 2, and 4 divided by 4 is 1, so they can both divide themselves by 4.

$\frac{5}{4}-\frac{1}{2}$

LCM

$\frac{5}{4}-\frac{2}{4} =\frac{3}{4}$

Therefore, the simplified expression to this is $21\frac{3}{4}$ .

Learn more: brainly.com/question/403991

8 0

2 years ago

In Australia, road distance is measured in kilometres.

maks197457 [2]

Answer:

Step-by-step explanation:

5 miles-8km

x miles-120 km

x=120×5÷8

x=75 (miles)

3 0

2 years ago

Read 2 more answers

PLZ HELP 70 POINTS!!!!!

marin [14]

5^(x+7)=(1/625)^(2x-13)

We move all terms to the left:

5^(x+7)-((1/625)^(2x-13))=0

Domain of the equation: 625)^(2x-13))!=0

x∈R

We add all the numbers together, and all the variables

5^(x+7)-((+1/625)^(2x-13))=0

We multiply all the terms by the denominator

(5^(x+7))*625)^(2x+1-13))-((=0

We add all the numbers together, and all the variables

(5^(x+7))*625)^(2x-12))-((=0

We add all the numbers together, and all the variables

(5^(x+7))*625)^(2x=0

not sure if this is right :/

8 0

2 years ago

Read 2 more answers

getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.

blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

Solution:

Given, Getting home from trick or treat celia and emma counted their candies. Half of celias candies is equal to 2/3 of emmas candies.

They had a total of 105 candies altogether.

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

$\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}$

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0

2 years ago

Which of the following does not belong to the solution set of -3x + 7 < 11?

erik [133]

-3x+7<11

-3x<4

x>-4/3

So anything less than or equal to -4/3 does not belong to the solution set.

With your update:

"The options is 4,-1,-5,and 0"

-5 does not belong to the solution set...

7 0

2 years ago

Read 2 more answers