4x + 3y = 5...(1)
2x + 3y = 1...(2)
(2)*2:
4x+6y=2...(3)
(1)-(3):
4x+3y-(4x+6y)=5-2
4x+3y-4x-6y=3
-3y=3
y=-1
By sub. y=-1 in (2), we have
2x+3(-1)=1
2x-3=1
2x=4
x=2
The solution is x=2,y=-1
Answer:
Step-by-step explanation:
k= 15
k+12 ≥ 20
15+12 ≥20
27 ≥ 20 True
2pt=1qt
1pt=1/2qt
therefor
multiply 2 and 3/4 by 1/2
(2 and 3/4) times 1/2=(2+3/4) times 1/2=2 times 1/2+3/4 times 1/2=2/2+3/8=1+3/8=1 and 3/8 pt
The 16th term is: 53
Further explanation:
We have to find the general formula first
The general form is:
The 16th term is: 53
Keywords: Arithmetic sequence, Common Difference
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