The answer is 28.
Check: 28-12= 16
1/4 of 16= 4
3/4 of 16= 12
so Carmen takes 3/4 more time of the trip to the market when she return s home.
Answer:
177 and 178
Step-by-step explanation:
First, the expression for the 2nd mile marker is x+1.
Now, you add x and x + 1 together to get 2x + 1
Next, make 2x + 1 equal to 355
Now subtract 1 and then divide by two on both sides to get x = 177.
This means that the first mile marker is 177 and the next is 178.
Answer:
p value from chi square = 0.081
Step-by-step explanation:
Given that sociologists say the percentage of the classic music lovers is about 5%. From the survey, we know that only 83 out of 2000 people listen to the classic music. Let denote the proportion of the classic music lovers. The hypotheses are H0: p=0.05 vs Ha: p≠0.05
p value = 0.09
Instead of this if we do chi square
H0: Proportion of music lovers is 5% and non music lovers is 95%
Ha: Proportions are not as per the estimate
(Two tailed chi square test)
Observed 83 1917 2000
Expected 100 1900 2000
O-E -17 17 0
chi square
(O-E)^2/E 2.89 0.1521 3.0421
df =1
p value from chi square = 0.081
Though p value is not exactly the same, the conclusion in both tests are the same
Answer:
W=50M
Step-by-step explanation:
Since there are 18 workers per 900 minerals, divide out to simplify.
STARTING EQUATION: 900m=18w
SIMPLIFY: divide both sides by 18.
SIMPLIFIED: 50m=1w
There is your answer!
The inequality that can be used to represents all possible combinations of x, the number of hamburgers and y, the number of briskets that will be cooked is 5y + 0.25x ≤ 150
Given:
pounds of brisket = 5 lb
Pounds of hamburger = 0.25 lb
Total pounds of briskets and hamburgers = no more than 150 lb
number of hamburgers = x
number of briskets = y
No more than in inequality = (≤)
The inequality:
5y + 0.25x ≤ 150
Therefore, inequality that can be used to represents all possible combinations of x, the number of hamburgers and y, the number of briskets that will be cooked is 5y + 0.25x ≤ 150
Learn more about inequality:
brainly.com/question/18881247
