Answer:
x=2 and y=−6
sorry this is pretty long, I did not know if you needed the steps or not
Step-by-step explanation:
−2y−10=x;−10x−y=−14
Solve−2y−10=x for x
−2y−10=x
−2y−10+−x=x+−x
−x−2y−10=0
−x−2y−10+2y=0+2y
−x−10=2y
−x−10+10=2y+10
−x=2y+10
-x/-1=2y+10/-1
x=−2y−10
Substitute−2y−10 for x in−10x−y=−14
−10x−y=−14
−10(−2y−10)−y=−14
19y+100=−14
19y+100+−100=−14+−100
19y=−114
19y/19=-114/19
y=-6
Substitute−6 for y in x=−2y−10
x=−2y−10
x=(−2)(−6)−10
x= 2
x=2 and y=−6
sin = 3/7
1 = sin²0 + cos²0
cos²0 = 1 - 9/49
cos²0 = 40/49
cos0 = √(40) / 7
since its in Quadrant 2 the sin is positive and cos is negative
cos0 = - √(40) / 7
Answer:
a rectangular field.The length of rectangular field is three times the breadth of the field. If the area of the path is 500 m square ,then find the length and breadth
A^3-19 should be the answer, good luck
Answer:
<u>a= -4</u>
Step-by-step explanation:
subtract 4a from both sides
add 15 to both sides
divide both sides by -3
(order of operations)
