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Dvinal [7]
4 years ago
10

A jawbreaker candy machine has 25 red jawbreakers, 30 green jawbreakers, 15 yellow

Mathematics
1 answer:
MArishka [77]4 years ago
7 0
<h3>Answer: Choice C, 2/3</h3>

============================================

Work Shown:

A = # of candies that are not green

A = (# of red)+(# of yellow)+(#  of blue)

A = 25+15+20

A = 60

B = # of candies total

B = (# of red)+(# of green)+(# of yellow)+(# of blue)

B = 25+30+15+20

B = 90

P(not green) = probability of selecting candy that is not green

P(not green) = (# of candies not green)/(# of candies total)

P(not green) = A/B

P(not green) = 60/90

P(not green) = (2*30)/(3*30)

P(not green) = 2/3

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Factor 15x^3-6x^2-25x+10 by grouping
Lostsunrise [7]

Answer: (5x-2)(3^2-5)

Step-by-step explanation:

So using the commutative property, we can change the equation 15x^3-6x^2-25x+10 into 15x^3-25x -6x^2+10

Let’s split that into two sections so it’s easier to see:

(15x^3-25x) - (6x^2+10)

Next let’s look at what 15x^3 and -25x have in common. They have 5x in common.

Factoring out 5x, we get this: 5x(3^2-5)

Next let’s look at what -6x^2and 10 have in common. They only have 2 in common, so we factor out 2.

2(-3^2+5) we can write this as -2(3^2-5)

So the end result will be : 5x(3^2-5)-2(3^2-5)

And the complete factorization will be (5x-2)(3^2-5)

7 0
4 years ago
Need help please<br> need help please<br> need help please<br> need help please
nexus9112 [7]
Hi! I’ll help you in just a moment when I’m done with my walk

7 0
3 years ago
A bag contains 11 tiles, one for each of the letters in the word BLUEBERRIES. You randomly choose a tile.
wel
2/11

there’s 2 R’s and 11 total so

possible outcomes/ overall outcomes
7 0
3 years ago
Help with this math picture :) worth 8 points
ipn [44]

Solving for x...
\frac{1}{2} x+ \frac{1}{4} =  \frac{15}{16} &#10;

Times the \frac{1}{2} , both the numerator and denominator, by 8 to get the denominator to 16.
Times the \frac{1}{4} , both the numerator and denominator, by 4 to get the denominator to 16.

Then rewrite the problem, 
\frac{8}{16}x+ \frac{4}{16} =  \frac{15}{16}

now that the denominators are all the same, you can solve...
subtract the \frac{4}{16} from both sides

you should get \frac{8}{16} x =  \frac{11}{16}

Multiply both sides by 16 (it'll cancel both the 16 out making it go away)
     8x = 11

divide each side by 8 to have the x alone

     <u>8x</u> = <u>11
</u>      8      8 
<u>
</u> You should end with x = \frac{11}{8} or 1.375<u>
</u>
3 0
3 years ago
The additional cost per month of a sunroof, spoiler and stereo is represented by three consecutive even integers, respectfully.
lesya [120]

Answer:

16

Step-by-step explanation:

First of all, I think it was "respectively", not "respecfully", =))). A noticeable point.

From the problem, three item's costs are represented by three consecutive even integer.

Thus, we can call cost of spoiler is x, sunroof is x-2, stereo is x + 2. It is conditioned that x is an even number.

Since the sum of the three is 48, we have

(x-2) + x + (x+2) = 48

x+x+x -2 +2 = 48

3x =48

x=16

So the spoiler is 16; thus, the sunroof is 14 and the stereo is 18

3 0
3 years ago
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