Answer:So, since it is continuously, we need to think of PERT
A=P\times e^{rt}
So, we just plug our numbers in to solve for T
8000=4000e^{.07t}\\\ln(8000)=\ln(4000e^{.07t})\\\ln(8000) = \ln(4000) + \ln(e^{.07t})\\\ln(8000)=\ln(4000)+.07t\ln(e)\\\ln(8000)=\ln(4000)+.07t\\\frac{\ln(8000)}{\ln(4000)}=.07t\\\frac{\ln(8000)}{.07\ln(4000)}=t\\ 15.479=t
It will take 15.479 years
Step-by-step explanation:
Answer:
y = -1/2x - 11/2
Step-by-step explanation:
y2 - y1 / x2 - x1
-4 - (-5) / -3 - (-1)
1/ -2
= -1/2
y = -1/2x + b
-5 = -1/2(-1) + b
-5 = 1/2 + b
-11/2 = b
<span>Number part = <span>3.3 </span></span>and
<span>Exponent part = -7</span>
<span>3.3*<span>10<span>−7</span></span></span>
Answer:
I'd say none, as we're missing something in this problem. Make sure you've included everything to solve this problem. Thanks.
A) 3(a - b) = 3*a +3*-b = 3a - 3b EQUAL
b) 2a(2 + b) = 4a + 2ab NOT EQUAL