Answer:
B has a smaller initial population of 500
Step-by-step explanation:
Given
See attachment for complete question
Required
The bacteria with the smaller initial population
The initial population is at x = 0
For bacteria A;
when
For bacteria B, we have:
Substitute 0 for x
So; when x = 0
and
Because; 500 < 600
We can conclude that B has a smaller initial population of 500
4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)
Answer:
0.15
Step-by-step explanation:
Because 5/8 divided by 4 is 0.15.
The absolute value of -6 is the distance it is away from 0. The absolute value would be |-6| or |6| to show that the numeral is 6 spots away from 0.
Answer:
Step-by-step explanation:
Calculate it together