Answer:
x=0, y=-12
Step-by-step explanation:
you can use substitution to solve for x
-3(x-12)=2x+36
-3x+36=2x+36
subtract 36 from both sides and add 3x to both sides
0=5x
x=0
now plug in 0 as x for either equation
y=0-12
y=-12
to check your work plug in x and y into the other equation
-3(-12)=2(0)+36
36=36
Answer:
2nd option
Step-by-step explanation:
Using the rule of exponents/ radicals
⇔ ![(\sqrt[n]{a}) ^{m}](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Ba%7D%29%20%5E%7Bm%7D)
, then
= ![(\sqrt[4]{10}) ^{3x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B10%7D%29%20%5E%7B3x%7D)
Answer:
the question is incomplete, so I looked for a similar one:
<em>After the release of radioactive material into the atmosphere from a nuclear power plant, the hay was contaminated by iodine 131 ( half-life, 8 days). If it is all right to feed the hay to cows when 10% of the iodine 131 remains, how long did the farmers need to wait to use this hay? </em>
iodine's half life (we are given x, we need to find b):
0.5A₀ = A₀eᵇˣ
x = 8 days
we eliminate A₀ from both sides
0.5 = eᵇ⁸
ln 0.5 = ln eᵇ⁸
-0.69315 = b8
b = -0.69315 / 8 = -0.08664
since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):
0.1A₀ = A₀eᵇˣ
0.1 = eᵇˣ
ln 0.1 = bx
where b = -0.08664
x = ln 0.1 / -0.08664 = -2.302585 / -0.08664 = 26.58 days
Answer:
x = 6
y = -9
x = -25
Step-by-step explanation:
<u>1st Equation</u>
Step 1: Write out equation
3(4x - 3) - 19 = 8x - 4
Step 2: Solve
12x - 9 - 19 = 8x - 4
12x - 28 = 8x - 4
4x - 28 = -4
4x = 24
x = 6
<u>2nd Equation</u>
Step 1: Write out equation
-6y + 14 = 32 - 4y
Step 2: Solve
-2y + 14 = 32
-2y = 18
y = -9
<u>3rd Equation</u>
Step 1: Write out equation
-28 + 5 - 3x = 2 - 2x
Step 2: Solve
-23 - 3x = 2 - 2x
-23 = 2 + x
-25 = x
x = -25
