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3 years ago

I need help please :(

Mathematics

1 answer:

algol [13]3 years ago

6 0

Answer:

Brainliest??!!!

Step-by-step explanation:

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I need some help with this problem can anyone help pls

Svet_ta [14]

Well we would need to see some type of graph in order to help you find the slope.

4 0

3 years ago

Need some help................

Diano4ka-milaya [45]

Answer:

its option B: r=(3xy)/(x-2y)

6 0

3 years ago

What is the value of 7P3 ? A. 21 B. 35 C. 210 D. 840<br><br> i think a but idk

Aleksandr [31]

The answer is C.
Here's why, nPr = n!/(n-r)!. Plug in 7 for n and 3 for r. And you get 7!/(7-3)!.
Thus, 7!/4! = (7*6*5*4*3*2*1)/(4*3*2*1), which simplifies to 7*6*5 = 210

6 0

3 years ago

Read 2 more answers

A florist owns two flower shops. The profit for the month of June at the first location can be represented by the function p(x)=

Dmitrij [34]

Answer:

$r(x) = 38x + 375$

Step-by-step explanation:

Given:

Profit in the month of June from first location is $p(x)=202+21x$

Profit in the month of June from second location is $q(x)=17x+173$

Now, total profit from the two locations can be obtained by adding the profits from each of the two locations.

Now, adding both the profits, we get:

$r(x)=p(x)+q(x)$

Plug in the given values and simplify. This gives,

$r(x)=202+21x+17x+173$

Now, we need to combine the like terms using commutative property.

Therefore, rearranging the terms, we get:

$r(x)=21x+17x+202+173\\\\r(x)=38x+375$

Therefore, the correct option is the first option.

5 0

3 years ago

What are the real zeroes of x3 + 6 x2 – 9x - 54?

o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of $x^3+6x^2-9x-54$

Solving

$x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)$

Taking x^2 common from first 2 terms and -9 from last two terms we get

$=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\$

Taking (x+6) common

$(x+6)(x^2-9)\\$

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

$=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)$

Putting it equal to zero,

$(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\, x=3$

So, Option B 3,-3,-6 is correct.

7 0

3 years ago

I need help please :(​

I need help please :(