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insens350 [35]
2 years ago
8

What is the solution to this system of equations y=x+6 and y=-.5x+3

Mathematics
1 answer:
juin [17]2 years ago
6 0

Answer:

x=-6, y=0

Step-by-step explanation:

it's impossible to fully solve an equation where 2 variables are unknown. So we have to make it equal to 1 set. to do this, we have to think logically.

if y=x+6, then that means wherever it says y, we can put x+6. because x+6=x+6, right? so we plug x+6 into the second equation and get.

x+6=0.5x+3

to solve for x we subtract 6 from one side and 0.5 from the other and get

0.5x=-3

then we multiply both sides by 2 to make be a whole number

x=-6

now we just plug this into either equation. because the first one is easier, we can just set it up as

y=(-6)+6

which means y=0

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if you have a bad credit score it can increase your debt ratio

Step-by-step explanation:

3 0
3 years ago
A machine cuts 25 circuit boards every 5 minutes. What is the unit rate of production for the machine?
irina1246 [14]

Answer:

25 divided by 5 = 5, so the unit rate is 5 circuit boards every minute.

8 0
3 years ago
(a) The function k is defined by k(x)=f(x)g(x). Find k′(0).
Brut [27]

Answer:

(a) k'(0) = f'(0)g(0) + f(0)g'(0)

(b) m'(5) = \frac{f'(5)g(5) - f(5)g'(5)}{2g^{2}(5) }

Step-by-step explanation:

(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use <u>product rule</u>,i.e., \frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}

this will give <em>k'(x)=f'(x)g(x) + f(x)g'(x)</em>

on substituting the value x=0, we will get the value of k'(0)

{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}

(b) m(x) is a function of two functions f(x) and g(x) [ m(x)=\frac{1}{2}\times\frac{f(x)}{g(x)} ]. Since m(x) has a function g(x) in the denominator so we need to use <u>division rule</u> to differentiate m(x). Division rule is as follows : \frac{\mathrm{d} \frac{f(x)}{g(x)}}{\mathrm{d} x}=\frac{\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}}{g^{2}(x)}

this will give <em>m'(x) = \frac{1}{2}\times\frac{f'(x)g(x) - f(x)g'(x)}{g^{2}(x) }</em>

on substituting the value x=5, we will get the value of m'(5).

{for expressing the value in terms of numbers first we need to know the value of f(5), g(5), f'(5) and g'(5) in terms of numbers}

{NOTE : in m(x), g(x) ≠ 0 for all x in domain to make m(x) defined and even m'(x) }

{ NOTE : \frac{\mathrm{d} f(x)}{\mathrm{d} x}=f'(x) }

4 0
3 years ago
A bottle of white wine at room temperature (68°f) is placed in a refrigerator at 4 p.m. its temperature after t hr is changing a
stiv31 [10]
After an hour (4pm to 5pm) the temperature drops 18e⁻⁰˙⁶=9.9℉, so the temperature after an hour will be 68-9.9=58.1℉.
(The change -18e⁻⁰˙⁶ is negative indicating a drop in temperature.)
4 0
3 years ago
Read 2 more answers
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 445445 gram setting. Is
marusya05 [52]

Answer:

Yes there is sufficient evidence.

Null hypothesis; H_o ; μ = 445

Alternative hypothesis; H_o ; μ ≠ 445

Step-by-step explanation:

The null hypothesis states that there is no difference in the test which is denoted by H_o. However, the sign of null hypothesis is denoted by the signs of = or ≥ or ≤.

Meanwhile, the alternative hypothesis is one that defers from the null hypothesis. This therefore implies a significant difference in the test. Thus, the signs of alternative hypothesis is denoted by; < or > or ≠.

Now, the question we have is a two tailed test. Thus;

The null hypothesis is;

bag filling machine works correctly at the 445 gram setting which is;

H_o ; μ = 445

The alternative hypothesis is;

bag filling machine works incorrectly at the 445 gram setting which is;

H_o ; μ ≠ 445

8 0
3 years ago
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