<h3>
Answer: The two factors are 5x+3 and x+1</h3>
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Explanation:
We could use the AC factoring method here. Multiply the first coefficient (10) with the last term (3) to get 10*3 = 30.
We need to find factors of 30 that add to 11
1+30 = 31
2+15 = 17
3+10 = 13
5+6 = 11
we have found the pair of factors that add to 11. So we'll break the 11x into 5x+6x and then use factor by grouping method
10x^2 + 11x + 3
10x^2 + 5x + 6x + 3
(10x^2 + 5x) + (6x + 3)
5x(2x + 1) + 3(2x + 1)
(5x+3)(2x+1)
We see the two factors are 5x+3 and 2x+1.
To check the answer, use either the box method, distribution, or FOIL rule to expand out (5x+3)(2x+1) and you should get 10x^2+11x+3 again.
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As an alternative, you can solve 10x^2+11x+3 = 0 through any method you prefer (graphing, completing the square, quadratic formula). The quadratic formula is the best option as it works for any quadratic. The two solutions you should get are x = -3/5 and x = -1/2
Using x = -3/5 and x = -1/2, we can do the following
- x = -3/5 becomes 5x = -3 after multiplying both sides by 5, then you add 3 to both sides to get 5x+3 = 0
- x = -1/2 becomes 2x = -1 after multiplying both sides by 2, and then turns into 2x+1 = 0 after adding 1 to both sides
Note how we have the 5x+3 and 2x+1 as found in the section above. At this point we can stop as we found the factors needed. I'm using the zero product property which says that if A*B = 0, then either A = 0 or B = 0.
Answer:
D. A value of 0.9 is more than 2 standard deviations from the mean
Step-by-step explanation:
In the figure attached, the distribution of data is shown.
From the picture we can see that:
- The data has a standard deviation of 0.15 (= 0.5 - 0.35 = 0.65 - 0.5)
- The mean of the data is 0.5
- A value of 0.7 is more than 1 standard deviation of the mean.
- A value of 0.9 is more than 2 standard deviations from the mean (0.8 is 2 standard deviations from the mean)
A linear equation is an equation with two variables whose graph is a line. The graph of the linear equation is a set of points in the coordinate plane that all are solutions to the equation. If all variables represent real numbers one can graph the equation by plotting enough points to recognize a pattern and then connect the points to include all points.
If you want to graph a linear equation you have to have at least two points, but it's usually a good idea to use more than two points. When choosing your points try to include both positive and negative values as well as zero.
Example
Graft the function y = x + 2
Begin by choosing a couple of values for x e.g. -2, -1, 0, 1 and 2 and calculate the corresponding y values.
X Y = x + 2 Ordered pair
-2 -2 + 2 = 0 (-2, 0)
-1 -1 + 2 = 1 (-1, 1)
0 0 + 2 = 2 (0, 2)
1 1 + 2 = 3 (1, 3)
2 2 + 2 = 4 (2, 4)
Now you can just plot the five ordered pairs in the coordinate plane
picture13
At the moment this is an example of a discrete function. A discrete function consists of isolated points.
By drawing a line through all points and while extending the line in both directions we get the opposite of a discrete function, a continuous function, which has an unbroken graph.
picture14
If you only want to use two points to determine your line you can use the two points where the graph crosses the axes. The point in which the graph crosses the x-axis is called the x-intercept and the point in which the graph crosses the y-axis is called the y-intercept. The x-intercept is found by finding the value of x when y = 0, (x, 0), and the y-intercept is found by finding the value of y when x = 0, (0, y).
picture15
The standard form of a linear equation is
Ax+By=C,A,B≠0
Before you can graph a linear equation in its standard form you first have to solve the equation for y.
2y−4x=8
2y−4x+4x=8+4x
2y=4x+8
2y2=4x2+82
y=2x+4
From here you can graph the equation as we did in the example above.
The graph of y = a is a horizontal line where the line passes through the point (0, a)
picture16
Whereas the graph of x = a is a vertical line that passes through the point (a, 0)
picture17
The answer is 44 if I’m not mistaken