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Oxana [17]
2 years ago
6

Please Help It Was Due Yesterday!!!! What is the 8th term in the Sequence? An=25-3n

Mathematics
2 answers:
nasty-shy [4]2 years ago
5 0

Answer:1

Step-by-step explanation:

Rudiy272 years ago
3 0

Answer:

a₈ = 1

Step-by-step explanation:

substitute n = 8 into the nth term rule

a₈ = 25 - 3(8) = 25 - 24 = 1

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Select all the roots of the following equation.
strojnjashka [21]

Answer:

5, -9

Step-by-step explanation:

(x - 5)(x + 9) = 0    These are factors, to get the roots, just set each one equal to zero

x - 5 = 0

x = 5

x + 9 = 0

x = -9

6 0
3 years ago
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Question above please help due in a few minutes
nexus9112 [7]

Answer:

Step-by-step explanation:

here x\geq3

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7 0
3 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
The second step in solving problems using order of operations is solving the
inna [77]
PEMDAS.....parenthesis, exponents, multiplication/division, addition/subtraction

so step 2 is solving the exponents <==
6 0
3 years ago
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396 times 37. explain how you got your answer
lara [203]

Answer:

14652

Step-by-step explanation:

calculator

4 0
3 years ago
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