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Mashcka [7]
3 years ago
6

Evaluate the function f(x)=tan^-1(x) when x=0. Give your answer in radians.

Mathematics
2 answers:
vichka [17]3 years ago
8 0
The answer is equal to 0.
Andrei [34K]3 years ago
8 0

Answer:

The value of the given function f(x) at x = 0 is 0

Step-by-step explanation:

The function is given to be :

f(x)=\tan^{-1}x

Now, we need to find the value of the given function f(x) when x = 0

So, To find f(0) we substitute x = 0 in the given function f(x)

\implies f(x)=\tan^{-1}x\\\\\implies f(0)=\tan^{-1}(0)\\\\\implies f(0)=\tan^{-1}(\tan 0)\\\\\implies f(0)=\tan^{-1}\tan(0)\\\\\implies f(0)=0

Therefore, The value of the given function f(x) at x = 0 is 0

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3 years ago
Write each expression in simplified radical form PLEASE HELP ITS DUE FRIDAY AND I DONT UNDERSTAND THIS AT ALL REALLY BAD TEACHER
Nonamiya [84]

Answer:

1) The simplified radical form is  \sqrt{36x^2}=6x

2) The simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) The simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) The simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

Step-by-step explanation:

1) Given expression is \sqrt{36x^2}

To find the simplified radical form of the given expression :

\sqrt{36x^2}

=\sqrt{36\times x^2}

=\sqrt{36}\times \sqrt{x^2}

=\sqrt{6\times 6}\times \sqrt{x\times x}

=6\times x

\sqrt{36x^2}=6x

Therefore the simplified radical form is  \sqrt{36x^2}=6x

2)Given expression is \sqrt{72x^3}

To find the simplified radical form of the given expression :

\sqrt{72x^3}

=\sqrt{72\times x^3}

=\sqrt{72}\times \sqrt{x^3}

=\sqrt{9\times 8}\times \sqrt{x\times x\times x}

=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}

=3\times 2\sqrt{2}\times x\sqrt{x}

\sqrt{72x^3}=6x\sqrt{2x}

Therefore the simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) Given expression is \sqrt{15x^8}

To find the simplified radical form of the given expression :

\sqrt{15x^8}

=\sqrt{15\times x^8}

=\sqrt{15}\times \sqrt{x^8}

=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}

=\sqrt{15}\times x^4

\sqrt{15x^8}=\sqrt{15}x^4

Therefore the simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) Given expression is \sqrt{36x^7}

To find the simplified radical form of the given expression :

\sqrt{36x^7}

=\sqrt{36\times x^7}

=\sqrt{36}\times \sqrt{x^7}

=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}

=6\times x^3\sqrt{x}

\sqrt{36x^7}=6x^3\sqrt{x}

Therefore the simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

3 0
3 years ago
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