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Mashcka [7]
3 years ago
6

Evaluate the function f(x)=tan^-1(x) when x=0. Give your answer in radians.

Mathematics
2 answers:
vichka [17]3 years ago
8 0
The answer is equal to 0.
Andrei [34K]3 years ago
8 0

Answer:

The value of the given function f(x) at x = 0 is 0

Step-by-step explanation:

The function is given to be :

f(x)=\tan^{-1}x

Now, we need to find the value of the given function f(x) when x = 0

So, To find f(0) we substitute x = 0 in the given function f(x)

\implies f(x)=\tan^{-1}x\\\\\implies f(0)=\tan^{-1}(0)\\\\\implies f(0)=\tan^{-1}(\tan 0)\\\\\implies f(0)=\tan^{-1}\tan(0)\\\\\implies f(0)=0

Therefore, The value of the given function f(x) at x = 0 is 0

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10, 5, 20, 10, 40, 20, 80, 40, 160, 80,

Next Three Numbers:  20, 80, 40

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Next, multiply the second term by 4. 5 times 4 = 20

Divide 20 by 4 to get 10

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Take half of 40 to get 20 (the first of the three missing terms)

Multiply 20 by 4 to get 80 (the second missing term)

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4 years ago
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4 years ago
The vertex of this parabola is at (4, -3). When the x-value is 5, the
NeTakaya
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Hope this helps you
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