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allsm [11]
2 years ago
13

What is the area of the shape?

Mathematics
2 answers:
marshall27 [118]2 years ago
6 0

Step-by-step explanation:

hello,

the shape is a right trapezium.

you use the following formula:

area of a trapezium = ½ × sum of parallel sides× height.

or simply,

a = ½ ( a + b ) h

where a and b are the parallel sides

and h is the height.

thus,

a = ½ × ( 4 + 6 )× 4

a = ½ ( 10 ) × 4

a = 5 × 4

a = 20

have a great day! au revoir !

Alla [95]2 years ago
6 0

Answer:20

Step-by-step explanation:you have to split the shape into one triangle in one square and then find out area of each shape.

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What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
Setler79 [48]

Answer:

k=-16,k=-8,k=8,k=16

Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

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now, we can multiply factor term

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we are given that

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15=(-1\times -15),(1\times 15)

15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

k=a+b

we can plug values

k=-1-15

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At (1\times 15):

k=a+b

we can plug values

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k=-3-5

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At (3\times 5):

k=a+b

we can plug values

k=3+5

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So, values of k are

k=-16,k=-8,k=8,k=16

6 0
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