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2 years ago

Image below ill give branliest

Mathematics

2 answers:

jenyasd209 [6]2 years ago

7 0

Answer:

(-1 , 5)

Step-by-step explanation:

Find the coordinates of the point after dilation:

A (-1,5) and B (-3,4)

Kruka [31]2 years ago

4 0

Answer:

It is(-1,5)

Step-by-step explanation:

You just divide the (-3,15) by 3 and you get your answer.

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What is the mode of the data set?

strojnjashka [21]

The data set is

32, 34, 36

40, 42, 44, 48

We can see that each value only shows up one time. Therefore there is no mode. To have a mode, we need to have a value show up more than once, and it must be the most frequent value. For example, the set {1,2,3,3,4} has a mode of 3 since it shows up twice, the most of any value in that set. However we don't have that occur for the data set your teacher gave you.

<h3>Final Answer: There is no mode for this data set</h3>

5 0

3 years ago

Write 3x 3x 3x 3 x 3 using exponents

Ahat [919]

$3\cdot3\cdot3\cdot3\cdot3=3^5$

5 0

3 years ago

Someone please help :) will mark brainliest :)

Nitella [24]

Answer:

a+b

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the value of angle y?

tankabanditka [31]

Value of angle Y is 180-51

8 0

3 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

4 0

3 years ago