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gavmur [86]
2 years ago
10

(3х3 – 17х2 + 15x — 25) (x — 5)

Mathematics
1 answer:
lakkis [162]2 years ago
3 0

Answer: 39

Step-by-step explanation: its very confusing so forgive me if im wrong

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Last question need help on this
lozanna [386]
The answer is B) which is letter E . hope this helps <3
6 0
2 years ago
Six and four fifths divided by three and two ninths
ahrayia [7]
Its going to be 4 .............
4 0
3 years ago
Suma numerelor de forma a4b cu produsul cifrelor 24 este egala cu
lyudmila [28]

Answer:

Raspuns corect: b)

Step-by-step explanation:

a4b=24, a×4×b=24⇒a×b=6

perechile de numere cu produsul 6 sunt: {1,6}  si {2,3}

a4b in baza 10=100a+40+b

100×1+40+6=146

100×6+40+1=641

100 ×2+40+3=243

100×3+40+2=342

146+641+243+342=1372

Raspuns corect: b)

6 0
3 years ago
Plz help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Eva8 [605]
I think the answer is C.

First start by factoring, you should get (2n-3)(n-2)=0

Then start to solve for n.

2n-3=0

n-2=0

n=2, n= 3/2

I hope that helps.
7 0
3 years ago
The symphonic choir and the jazz choir are recording songs for an album. The album can be no more than 72
Brut [27]

Answer:

The maximum number of songs that the symphonic choir can record is 14

Step-by-step explanation:

Let

x ----> the number of songs of the symphonic choir

we know that

The number of songs of the jazz choir multiplied by its average time per song plus the the number of songs of the symphonic choir multiplied by its average time per song, must be less than or equal to 72 minutes

so

The inequality that represent this situation is

3(7)+3.5(x)\leq 72

solve for x

21+3.5x\leq 72

subtract 21 both sides

3.5x\leq 51

divide by 3.6 both sides

x\leq 14.6\ songs

therefore

The maximum number of songs that the symphonic choir can record is 14

3 0
3 years ago
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