Answer:
25a2b2+4a2b+6ab2-4ab+7
Step-by-step explanation:
=sum of two polynomials -one addend
=20a2b2-8a2b+6ab2-4ab+2-(-5a2b2+12a2b-5)
=20a2b2-8a2b+6ab2-4ab+2+5a2b2-12a2b+5
=25a2b2+4a2b+6ab2-4ab+7
Answer:
Its D. -14
Step-by-step explanation:
The slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
Given that the points through which the line passes is (19,-16) and (-7,-15).
We are required to find the slope of the line which passes through (19,-16) and (-7,-15).
The slope of a line is basically a measure of its steepness.It is basically the difference between y coordinate divided by the difference between x coordinate. We can form an equation with the help of the slope.
Points=(19,-16) and (-7,-15)
Slope=(-15+16)/(-7-19)
=1/-26
=-1/26
Hence the slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
Learn more about slope at brainly.com/question/3493733
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Answer:
n = 16
Step-by-step explanation:
3^4(81^2) = 3^n
3^4(3^4) = 3^n
3^16 = 3^n
n = 16
Answer:
J'(2, 1)
K'(0, 3)
Step-by-step explanation:
On a coordinate plane, coordinates of the points J, K and L are (-2, 1), (0, 3) and (2, -1) respectively.
If we reflect these points over the line x = 0 or y-axis, rule to be followed is
(x, y) → (-x, y)
Only sign of x coordinates get changed while y coordinates remain the same.
Following this rule coordinates of the images of J' and K' will be
J(-2, 1) → J'(2, 1)
and K(0, 3) → K'(0, 3)
