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FrozenT [24]
2 years ago
7

F(x)=2 to the power of x +3 what is the value of f(-2)

Mathematics
1 answer:
aleksklad [387]2 years ago
3 0

Answer:

2

Step-by-step explanation:

f(x) = 2^(x+3)      

f(-2) = put in -2 where x is

      = 2 ^(-2+3) = 2^1 = 2  

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Help please. If correct I’ll mark as brainliest but I rlly need help.
kykrilka [37]

Answer:

46

Step-by-step explanation:

x +3x+5x - 54 = 360

x +3x+5x = 360 + 54

9x = 414

x= 46

4 0
3 years ago
PLEASE HELP<br> Find the length of the missing side.
BabaBlast [244]

Answer:

use Pythagoras theorem

the missing side is base

Step-by-step explanation:

pythagoras theorem

h^2 = p^2 + b^2

73^2 = 48^2 + b^2

5329 = 2304 + b^2

5329 - 2304 = b^2

3025 = b^2

√3025 = b

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3 0
2 years ago
What is 6920 divided by 4
7nadin3 [17]

ANSWER

ITS ANSWER IS 1730

6 0
3 years ago
Read 2 more answers
MEDAL !!! TRUE OR FALSE. Jonathan is catering an event for one of his clients. He has a maximum of $200 to spend on appetizers.
DochEvi [55]

182.5 US dollars so yes

the answer is True

5 0
3 years ago
) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.
snow_tiger [21]
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
   5 -1 -6
   1  1  1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0

Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
5 0
3 years ago
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