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MAVERICK [17]
2 years ago
15

Courtney is playing miniature golf. What is the area of the composite figure.

Mathematics
1 answer:
uysha [10]2 years ago
8 0
18. It is 18 because when you multiply 2x2 plus 4 x2 plus 2 x3 you get 4 plus 8 plus 6 = 18
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If the cos of angle x is 8 over 17 and the triangle was dilated to be two times as big as the original, what would be the value
Viktor [21]

Answer:

the answer is 8/17

Step-by-step explanation:

i got it right on the quiz

6 0
3 years ago
Of the 35 students in my class, 11 practice karate, 11 play piano, and 20 take math lessons. $ students play piano and go to mat
Andrews [41]
There are twenty four students that do all
4 0
3 years ago
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Which equation can be used to solve for the measure of angle abc? tan(x) = startfraction 2.4 over 10 endfraction tan(x) = startf
Len [333]

The equation can be used to solve for the measure of angle abc is sinx = 2.4/10.3

<h3 /><h3>SOH CAH TOA identity</h3>

The identity is used to find the measure of sides and acute angles of a right triangle

From the diagram shown, <ABC is the reference abgle hence;

Opposite side = 2,4cm

Hypotenuse .=10.3cm

According to the identity

sin x = opp/hyp

sinx = 2.4/10.3
sinx = 0.233

x =  13.47 degrees

Hence the equation can be used to solve for the measure of angle abc is sinx = 2.4/10.3

Learn more on SOH CAH TOA here: brainly.com/question/20734777

3 0
2 years ago
pls There are (4^9)^5 ⋅ 4^0 books at the library. What is the total number of books at the library? A.4^9 B. 4^45 C. 4^46 D. 1  
jekas [21]
We know that there are (4^9)^5 ⋅ 4^0 at the library, so we just need to simplify this to get the answer.
(4^9)^5 ⋅ 4^0
=(4^9)^5×1
=(4^9)^5
=4^9×5
=4^45. As a result, the total number of books at the library is 4^45 books at the library or B is the final answer. Hope it help!
6 0
3 years ago
the volumes of two similar figures are 729 mm and 2744 mm if the surface area of the larger figure is 392 mm what is the surface
Stolb23 [73]
We know that
[volume of larger figure]=[scale]³*[volume of smaller figure]
scale=∛(volume of larger figure/volume of smaller figure)
scale=∛(2744/729)-----> 1.56

[surface area of the larger figure]=scale²*[<span>surface area of the smaller figure]
</span>[surface area of the smaller figure]=[surface area of the larger figure]/scale²
[surface area of the smaller figure]=[392]/1.56²----> 162 mm²

the answer is
the surface area of the smaller figure is 162 mm²
7 0
3 years ago
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