2^3z^9
A for question 1=8z^9
(-8ab)^2
(-8^2a^2b^2)
A for question 2=64a^2b^2
6 (x^3)^2
6 x^6
6x^6
Enjoy!=)
Answer:
-50
Step-by-step explanation:
This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
The median is the middle-most number. First we need to put the numbers in order from lowest to highest:
81 84 88 94 94 96
The easiest way to find the median is to cross out the first and last number and then continue until you reach the middle.
So cross out 81 and 96:
84 88 94 94 are left.
Cross out 84 and 94:
88 and 94 are left.
Since we are left with 2 different numbers, we need to find the average of them and that’s our median. (88 + 94)/2 = 91
91 is the median.
13 is C, √10
Rational numbers are numbers that can be expressed as a ratio, or a fraction.
14 is C, 9.5 × 10^5
