Answer:
1339.75
Step-by-step explanation:
No, you will have remainder.
The number of participants with laptop is 115 and without laptop is 161
<u>Step-by-step explanation:</u>
Total number of participants= 276
Participants with laptop = (5/12) 276
= 115
Participants without laptop= 276 - 115
= 161
A. (8,4) because you can tell in the second pattern
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
6
Step-by-step explanation:
=> -x+4
<u><em>Given that x = -2</em></u>
=> -(-2)+4
=> 2+4
=> 6
