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laiz [17]
3 years ago
14

6.

Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0
Focus (0,6), dirextrix y=-6
it’s the third one
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You recently saw a news article that included this graph and had the title “A Nation of Procrastinators”. What evidence from the
user100 [1]

Answer: The graph shows that people procrastinate by doing their taxes mostly in April then in the beginning of the year in January

Step-by-step explanation: think about it the name in the title has procrastinated in it which means holding off for a certain amount of time, then look at the graph most the people held off until April, why must you ask? Because the taxes are higher in the beginning of the year

3 0
3 years ago
It’s easy please help please please
lions [1.4K]

Step-by-step explanation:

4x - 2y = 8

y = -2

4x -2(-2) = 8

4x + 4 = 8

4x = 4

x = 1

5 0
3 years ago
 In The Diagram, P, Q, R, Are Points On The Circle With Centre 0 And Diameter 14cm. Angle PQR=35 Degree. Find, Correct To One De
patriot [66]

Answer:

a

Step-by-step explanation:

because the diagram the length decimal place degree

8 0
3 years ago
Which of the following graphs would represent the solution set for y<6x-2
OverLord2011 [107]
Where is the graph but in this case the y intercept would be -2 and you slope is 6 so go up 6 and to the right one and go down six and to the left one and thats what the graph should look like
5 0
4 years ago
Read 2 more answers
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
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