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Travka [436]
3 years ago
8

Pls help (brainliest) (deleting links!!!)

Mathematics
1 answer:
VikaD [51]3 years ago
5 0

Answer:

3rd one idrk hope it's right

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Karen operates a hot dog stand. On Wednesday she used 9 1/3 bags of hot
trapecia [35]
<h2>Explanation:</h2>

We know that Karen operates a hot dog stand. So we have:

<u>On Wednesday:</u>

<u></u>

<u></u>\text{She used} \ 9 \frac{1}{3} \ \text{bags of hot dog buns.}<u></u>

<u></u>

<u>On Thursday:</u>

<u></u>

<u></u>\text{She used} \ \frac{1}{3} \ \text{as many hot dog buns as on Wednesday}<u></u>

<u></u>

Therefore, if x is the amount of hot dog buns she used on Thursday, then:

x=\frac{1}{3}(9\frac{1}{3}) \\ \\ x=\frac{1}{3}\times 9+\frac{1}{3}\times \frac{1}{3} \\ \\ x=\frac{28}{9}

Therefore, on Thursday she used 28/9 bags of hot  dog buns.

6 0
3 years ago
I really need help please someone
Lilit [14]

Step-by-step explanation:

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3 0
3 years ago
0.05 is 1/10 the value of
Dominik [7]
0.5, 0.05 is 1/10 the value of 0.5
7 0
4 years ago
Evaluating integral by net area
N76 [4]

The graph of f(x)=2 is a horizontal line. So the area under f(x) on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of g(x)=\sqrt{64-x^2} is the upper half of a circle with radius \sqrt{64}=8. It's symmetric about x=0, so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is \frac{\pi 8^2}4=16\pi.

Then use the fact that the definite integral is distributive over sums, meaning

\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi

8 0
4 years ago
5y&gt;30 help me please
ivanzaharov [21]

Answer:

y>6

Step-by-step explanation:

5y>30

y>30/5

y>6

4 0
3 years ago
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