Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, A
1 answer:
Given: ABCD ∥gram,
BK ⊥ AD , AB ⊥ BD
AB=6, AK=3
Find: m∠A, BK
To proof
as given BK ⊥ AD
thus ΔABK is a right triangle.
thus by using the pythagoras theorem
we have
AB² = BK² + AK²
BK² = AB ²- AK²
= 6² - 3²
= 36 - 9
= 27
Hence
BK = <u> unit</u>
Now find the value m∠A
by using the trignometric function
FORMULA
cosA =
cosA =
=
m∠A = 60°
hence proved
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Answer:
B) Both functions have the same domain.
C) Both functions have the same x-intercepts.
D) Both functions are decreasing on the interval (−∞, −2).
Step-by-step explanation:
step 1
Find the vertex of f(x)
we know that
The x-coordinate of the vertex is the midpoint of the roots
we have
x=-1 and x=-3
so
the midpoint is
(-1-3)/2=-2
The y-coordinate of the vertex is -4 (because the range is [−4, ∞))
therefore
The vertex of f(x) is the point (-2,-4)
Is a vertical parabola open upward
The vertex is a minimum
The domain is all real numbers
step 2
we have
Find the vertex
Factor the leading coefficient
Complete the square
Rewrite as perfect squares
Is a vertical parabola open upward
The vertex is the point (-2,-2)
The domain is all real numbers
The range is the interval [−2, ∞)
Find the x-intercepts
For g(x)=0
so
The roots or x-intercepts are
x=-1 and x=-3
<u><em>Verify each statement</em></u>
A) Both functions have the same vertex
The statement is false
The vertex of f(x) is (-2,-4) and the vertex of g(x) is (-2,-2)
B) Both functions have the same domain.
The statement is true
The domain is all real numbers
C) Both functions have the same x-intercepts
The statement is true (see the explanation)
D) Both functions are decreasing on the interval (−∞, −2)
The statement is true
Because the x-coordinate of the vertex is the same in both functions, and both functions open upward