Answer:
The answer is 5
Step-by-step explanation:
I took the test :)
If the take the origin as the starting point of the ball, then the vertex would be (4,28) and the parabola would be facing downwards. Using the general form of the parabola which is (x-h)^2 = 4p(y-k) where h and k are taken from the coordinate of the vertex (h,k).
So, the equation would be, (x-4)^2)=4p(y-28). To determine 4p, we can substitute either of the two points: (0,0) or (0,8). The second coordinate is taken from the given that the ball covers a distance of 4 ft after it reaches a maximum height. The total distance traveled by the ball is twice that, which is 8 ft.
After substituting, 4p = -4/7. Plugging this into the equation and after expanding and simplifying, the equation of the ball's trajectory is:
y = (-4/7)x^2+14x
The question is asking to states the value of the z-score of a value that is 2.08 standard deviations greater than the mean and base on my research, the possible answer would be z-score is the number of standard deviations above the mean. <span>If you are 5 standard deviations above the mean, that is defined as z = 5. </span><span>If you are 1.1 standard deviations above the mean, that is defined as z = 1.1. </span>
<span>And so if you are 2.08 standard deviations above the mean</span>
Answer:
6 cm
Step-by-step explanation:
First find the height of 1 foot by doing 1/6 = 1.66. Then multiply that by the height of the robot. 1.66 x 36 = 6.
⓵ When two angles are completely, it means that the the sum of the two angles together is 90°!
⓶ Knowing that, if your angle a is 42°, you need to subtract 42° from 90° in order to have the measure of your angle b!
⓷ You can have different equations depending on what you are looking for.
For example, you could write that :
× = 90° - angle a
Or you could writhe that :
× = (angle a + angle b) - angle a
I’m not sure what kind of equation you are looking for, but as long as your equation (so ×) equals 48° (90° - 42°), I think you should be fine!
I really hope this helps, if there’s anything let me know! ☻