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lisov135 [29]
3 years ago
14

2. |X-6|+ 1 =- 2x + 4

Mathematics
1 answer:
devlian [24]3 years ago
4 0

Answer:

i dont understand the question you are asking

Step-by-step explanation:

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Examine the figure below.
goldfiish [28.3K]

The correct angle measures are m/JKL = 37° and mZKLM = 126°. Option A and C

<h3>How to determine the angle</h3>

Given that;

∠ K =  (4x + 5)°

∠ J = 6x + 1

∠ L = 8x + 30 = 180 ( angles on a straight line)

Note that the sum of the angles of a triangle is 180°

∠ K + ∠ J  + ∠ L = 180

6x + 1 + 4x + 5 + 8x + 30 = 180

collect like terms

18x = 180 - 36

18x = 144

Make 'x' the subject

x = 144/ 18

x = 8

Substitute the values

∠ JKL = (4x + 5)° = 4(8) + 5 = 37°

∠KJ L  = (6x + 1)° = (6(8) + 1) = 49°

∠ KLM = 8x + 30 = 8(8) + 30 = 94°

∠ JLK = 8x + 30 = 180 = 180 - 94 = 86°

Thus, the correct angle measures are m/JKL = 37° and mZKLM = 126°. Option A and C

Learn more about a triangle here:

brainly.com/question/7620723

#SPJ1

5 0
2 years ago
Which of the following are an x-intercept?
Vadim26 [7]

Answer for question 2:

x= -5

Step-by-step explanation:

0= 6x +30

-6x= 30

x= 30/-6

x= -5

4 0
3 years ago
(sinA-cosA+1)/(sinA+cosA-1)=2(1+cosecA)​
borishaifa [10]

Answer:

The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

Step-by-step explanation:

Given Trigonometrical function as :

\frac{sin A - cos A + 1}{sin A + cos A - 1} = 2 (1 + cosec A)

Or, \frac{sin A + ( 1 - cos A)}{sin A - (1 - cos A)} = 2 (1 + cosec A)

,<u> Now, rationalizing </u>

\frac{(sin A + ( 1 - cos A)) \times (sin A + (1 - cosA))}{(sin A - (1 - cos A))\times (sin A + (1 - cos A))} = 2 (1 + cosec A)

Or, \frac{(sin A + (1 - cos A))^{2}}{sin^{2} - (1-cos A)^{2}} = 2 ( 1 + \dfrac{1}{\textrm sinA}

Or, \frac{sin^{2}A + (1 - cosA)^{2} + 2 \times sin A \times (1 - cos A)}{sin^{2}A - (1 + cos^{2}A - 2 cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - 1 - cos^{2}A +2 cos A} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - (sin^{2}A + cos^{2}A) - cos^{2}A +2 cos A} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{2- 2 cos A + 2 sin A - 2 sin A cos A}{- 2cos^{2}A +2 cos A} =  2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{1-  cos A +  sin A -  sin A cos A}{- cos^{2}A + cos A} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{(1-  cos A) +  sin A (1-cos A)}{cos A(1 - cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{(1-  cos A) (1 + sinA)}{cos A(1 - cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, \frac{(1 + sinA)}{(cos A)} = 2 ( \dfrac{1 + sin A}{sin A}

Or, sin A + sin² A = 2 cos A (1 + sin A)

Or,  sin A + sin² A = 2 cos A + 2 cos A × sin A

Or,   sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

So,The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0     Answer

6 0
3 years ago
Develop a probability model <br> for the spinner shown.​
Tatiana [17]

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Look at the photo I need help
HACTEHA [7]

Plug 3 in for r it equals 28.26 so its A

4 0
4 years ago
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